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Lorico [155]
2 years ago
15

Recall all the models you described in task 1.(Bohr, Rutherford, Thomson, and Dalton) Think about the results each model would p

redict for Thomson’s experiment. Which atomic models does Thomson’s experimental evidence support? Explain why these models are compatible with the experimental results.
Chemistry
1 answer:
Leya [2.2K]2 years ago
7 0

Thomson's experimental data does support the Rutherford model.

<h3></h3><h3>What is an atom?</h3>

The atom consists of matter that may be split without releasing electrical charges.

It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.

Rutherford was the one who first published the nuclear model of the atom. According to his atomic model, an atom's volume is largely empty,

The center of the atom houses the nucleus, which is made up of protons and neutrons, and its electrons follow certain pathways as they orbit it.

When compared to Rutherford's discoveries, the study of certain other scientists, like Dalton, Neil Bohr, and JJ Thomson, is mostly consistent.

For instance, Dalton's atomic theory assumed that atoms interact to create compounds and are nearly the same size.

Rutherford's theory states that atoms have a finite amount of electrons that may be shared to form compounds.

Rutherford's discoveries, which gave rise to the concept of shells, are also consistent with the Bohr model, which holds that electrons orbit the nucleus in certain shells.

Despite the fact that Rutherford's model was the best atomic model, it nevertheless drew from a number of prior studies and was compatible with their findings.

Hence Thomson's experimental data does support the Rutherford model.

To learn more about the atom refer to the link;

brainly.com/question/1566330

#SPJ1

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mr_godi [17]
4Al + 3O₂ ----> 2Al₂O₃
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4 0
4 years ago
How does rhenium apply to real life​
riadik2000 [5.3K]

Answer: Rhenium is used as an additive to tungsten- and molybdenum-based alloys to give useful properties. These alloys are used for oven filaments and x-ray machines. It is also used as an electrical contact material as it resists wear and withstands arc corrosion.

Explanation:

4 0
3 years ago
Calculate the standard molar enthalpy of formation, in kJ/mol, of NO(g) from the following data:
Paraphin [41]

The above question is incomplete, here is the complete question:

Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o= -114.1 kJ

Answer:

The standard molar enthalpy of formation of NO is 90.25 kJ/mol.

Explanation:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o_{1} = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o_{2} = -114.1 kJ

To calculate the standard molar enthalpy of formation

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?...[3]

Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[1] - [2] = [3]

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?

\Delta H^o_{3} =\Delta H^o_{1} - \Delta H^o_{2}

\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ

According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :

=\frac{\Delta H^o_{3}}{2 mol}

=\frac{180.5 kJ}{2 mol}=90.25 kJ/mol

3 0
3 years ago
Please help :(. <br><br> Which is true about scientific theories?
Romashka-Z-Leto [24]
I think the answer is c
4 0
3 years ago
Read 2 more answers
A student finds two unlabeled flasks of clear liquids. One is believed to be 0.1 m nacl and the other to be 0.1 m naclo3. What i
KonstantinChe [14]

Answer:

  • Add AgNO₃ solution to both unlabeled flasks: based on solubility rules, you can predict that when you add AgNO₃ to the NaCl solution, you will obtain AgCl precipitate, while no precipitate will be formed from the NaClO₃ solution.

Explanation:

<u>1. Adding AgNO₃ to NaCl solution:</u>

  • AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

<u>2. Adding AgNO₃ to NaClO₃ solution</u>

  • AgNO₃ (aq) + NaClO₃ (aq) → AgClO₃ (aq) + NaNO₃ (aq)

<u />

<u>3. Relevant solubility rules for the problem.</u>

  • Although most salts containing Cl⁻ are soluble, AgCl is a remarkable exception and is insoluble.

  • All chlorates are soluble, so AgClO₃ is soluble.

  • Salts containing nitrate ion (NO₃⁻) are generally soluble and NaNO₃ is not an exception to this rule. In fact, NaNO₃ is very well known to be soluble.

Hence, when you add AgNO₃ to the NaCl solution the AgCl formed will precipitate, and when you add the same salt (AgNO₃) to the AgClO₃ solution both formed salts AgClO₃ and NaNO₃ are soluble.

Then, the precipiate will permit to conclude which flask contains AgCl.

6 0
3 years ago
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