If the heat of fusion of ice is 335 j/g, how much heat is needed to melt 4.36 g of ice at 0.0 °c?
1 answer:
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Answer:
The mass of HCN is 79.65 g.
The mass of reactant which remain at the end of both reactions is 88.5 g.
Explanation:
Given that,
Mass of ammonia = 50.2 g
Mass of methane = 48.4 g
Hydrogen cyanide, HCN, can be made by a two-step process
Ammonia reacts with O₂ to give nitric oxide NO.
The reaction is,
We need to calculate the mole of NO
Using given data,
2.25 g NH_{3}=\dfrac{50.2}{17}= 2.95\ mole\ NH_{3} [/tex]
2.95 mol NH₃ will produced 2.95 mol NO
Then nitric oxide reacts with methane,
The reaction is,
We need to calculate the mole of methane
Using given data,
2 mole NO produced 2 mole HCN
2.95 mol NO will produced = 2.95 mol HCN
We need to calculate the mass of HCN
Using formula of mass
Where, N = number of mole
M = molecular mass
Put the value into the formula
The mass of HCN is 79.65 g.
We need to calculate the mass of NO
Using formula of mass
Where, N = number of mole
M = molecular mass
Put the value into the formula
Hence, The mass of HCN is 79.65 g.
The mass of reactant which remain at the end of both reactions is 88.5 g.
☃️ Chemical formulae ➝
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>
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