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PolarNik [594]
3 years ago
8

Two chemist are trying to determine if their water sample is a mixture or pure substance. In their investigation they first filt

er the sample of dirty water with gravel. The water is then clearer then before. See image. What does this change tell the chemist about the chemical make up of the sample
The dirty water is only a mixture because it was not completely filtered by the gravel.


Dirty water is a mixture of solid particles and liquid. It is both a mixture and pure substance.


More information is needed to answer the question.


The dirty water is only a pure substance now that it has been filtered by the gravel
Chemistry
1 answer:
Effectus [21]3 years ago
8 0

The correct answer is option B. Dirty water is a mixture of solid particles and liquid. It is both a mixture and pure substance.

The dirty water sample has both gravel and liquid water in it. After filtration the gravel is removed so the water sample looks clearer than before filtration. Liquid water is a pure substance because it is a compound that is made up of elements hydrogen and oxygen. Now the gravel is only physically combined with the liquid water, thus giving the water sample properties of a mixture. And like any mixture, gravel is physically separated through filtration from the liquid water.

Thus the water sample of the chemists is both a mixture and pure substance.




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D. is the answer
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3 years ago
Thanks for the help :) Question attached below:
Alekssandra [29.7K]

• Take a look at the steps below to see how to balance this equation. Let's start by writing the unbalanced equation given the information.

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Start by Balancing the Carbons : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + H₂O (g)

Now let's balance the Hydrogen : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + 4H₂O (g)

Balancing the Oxygen : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)

Balanced Equation : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)

• Let's apply dimensional analysis here,

0.7 L propane × (5 liters Oxygen / 1 liter Propane) = 3.5 Liters of Oxygen

•  Similarly we can identify the liters of carbon dioxide produced in the reaction,

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• 0.7 L propane × (4 liter water vapor / 1 liter propane ) = 2.8 Liters of Water Vapor

7 0
3 years ago
Consider the reaction. mc015-1.jpg How many grams of N2 are required to produce 100.0 L of NH3 at STP?
Nadusha1986 [10]
The  grams  of N2  that  are   required   to  produce 100.0 l  of  NH3   at  STP

At  stp 1moles = 22.4  l. what  about  100.0 L of NH3

= 100 / 22.4 lx1  moles = 4.46  moles  of NH3

write the reacting  equation

N2+3H2 =2NH3
by use of mole  ratio  between  N2  to NH3  which is  1:2 the moles of N2 =4.46/2 =2.23  moles of N2

mass =  moles  x  molar  mass

=  2.23moles  x 28  g/mol =  62.4 grams
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kakasveta [241]
No entiendo cual es tu pregunta?
3 0
3 years ago
First, get about 20 mL of the quinine stock solution in a clean beaker to prepare 250 mL of about 2 ppm quinine in 0.05 M H2SO4.
iris [78.8K]

Answer:

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Va*Ca=Vb*Cb

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5 0
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