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PolarNik [594]
3 years ago
8

Two chemist are trying to determine if their water sample is a mixture or pure substance. In their investigation they first filt

er the sample of dirty water with gravel. The water is then clearer then before. See image. What does this change tell the chemist about the chemical make up of the sample
The dirty water is only a mixture because it was not completely filtered by the gravel.


Dirty water is a mixture of solid particles and liquid. It is both a mixture and pure substance.


More information is needed to answer the question.


The dirty water is only a pure substance now that it has been filtered by the gravel
Chemistry
1 answer:
Effectus [21]3 years ago
8 0

The correct answer is option B. Dirty water is a mixture of solid particles and liquid. It is both a mixture and pure substance.

The dirty water sample has both gravel and liquid water in it. After filtration the gravel is removed so the water sample looks clearer than before filtration. Liquid water is a pure substance because it is a compound that is made up of elements hydrogen and oxygen. Now the gravel is only physically combined with the liquid water, thus giving the water sample properties of a mixture. And like any mixture, gravel is physically separated through filtration from the liquid water.

Thus the water sample of the chemists is both a mixture and pure substance.




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How many cm3 are contained in 3.83 x 107 mm3?
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Answer:

3.38 x 10⁴cm³

Explanation:

Given that:

      Volume of the substance  = 3.83 x 10⁷mm³

The problem entails use to convert from mm³ to cm³;

                    1000mm³   = 1cm³

So;

          3.83 x 10⁷mm³ will produce \frac{ 3.83 x 10^{7} }{1000}    = 3.38 x 10⁴cm³

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2 years ago
Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
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2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

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Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

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n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

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Moles of NaOH left unreacted  in the solution =

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NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

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The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

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