Question

A wire of a given material has an electric field of 0.100 mV/m when a potential is applied. The wire has 8.49 x 1028 conduction electrons per cubic meter and a mean free time between collisions of 2.50 x 10-14 s. What is the uniform current density in the wire

Answer 1

The uniform current density in the wire is 5.43 x 10²⁷ A/m².

Current density in the wire

The uniform current density in the wire is calculated as follows;

J = total current / total area

The given parameters:

• Conduction of the wire = 8.49 x 10²⁸ e/m²
• time, t = 2.5 x 10⁻¹⁴ s

$J = \frac{I}{A} = \frac{Q}{At} \\\\J = \frac{8.49 \times 10^{28}e/m^3 \ \times \ 1.6 \times 10^{-19} \ C/e}{2.5 \times 10^{-14} \ s \ \times ( 0.1 \times 10^{-3} \ V/m)} \\\\J = 5.43 \times 10^{27} \ A/m^2$

Learn more about current density here: brainly.com/question/15266434

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