Answer:
velocity zero and acceleration negative
Explanation:
According to the directions taken in the vector analysis, the direction which is upwards taken as positive, the direction which is downwards is taken as negative.
The direction which is rightwards taken as positive and the direction which is leftwards taken as negative.
here, ball throws vertically upwards and it attains a maximum height. At maximum height the magnitude of velocity is zero but the acceleration is always acting downwards so it is taken as negative in sign.
Answer:
9.4 m/s
Explanation:
The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.
So we can write:
where in this problem:
W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)
is the initial kinetic energy of the car
is the final kinetic energy
Solving for Kf,
The kinetic energy of the car can be also written as
where:
m = 661 kg is the mass of the car
v is its final speed
Solving, we find
Gravitational potential energy=mass*gravitational acceleration*height
Kinetic energy = 0.5*mass*velocity²
So with the given data
K.E 0.5*1*x²=12.5 v²=12.5÷(0.5*1)
v=√12.5÷(0.5*1) v=5
GPE mass*gravitational acceleration*height
1*9.81*h=98
h=98÷(9.81*1)
h= 9.98 m
The slope of the line on a velocity vs. time graph represents acceleration
