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3 years ago

The medium at point P will?

Physics

1 answer:

Tanya [424]3 years ago

3 0

<h2>Answer: remain stationary</h2>

Stationary waves (so called because they seem to be immobile) occur when two waves interfere with the <u>same frequency, amplitude but with different direction</u>, along a line with a phase difference of half wavelength.

In this kind of waves there are two types of points:

The nodes, which are points that remain motionless or stationary and do not vibrate. They are due to the destructive interference of both waves when they meet.

The antinodes, which are points that vibrate with a maximum vibration amplitude. They are due to the non-destructive interference of both waves.

According to this explanation and comparing it with the description, when this two waves pass through each other, the point P will become a node, hence<u> it will remain stationary</u>.

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Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.

ankoles [38]

Answer:

The correct answer is - 200000 J

Explanation:

We use the formula of kinetic energy:

The formula to calculate kinetic energy is,

Here,

Ec =1/2 x m x v^2

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3 years ago

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3 years ago

A spring with a force constant of 5.2 N/m has a relaxed length of 2.45 m. When a mass is attached to the end of the spring and a

Elodia [21]

Answer:

Elastic potential energy, E = 3.26 J

Explanation:

It is given that,

Force constant of the spring, k = 5.2 N/m

Relaxed length of the spring, X = 2.45 m

When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m

To find,

The elastic potential energy stored in the spring.

Solution,

The extension in the length of the spring is given by :

$x=x'-X$

$x=3.57\ m-2.45\ m$

x = 1.12 m

The elastic potential energy of the spring is given by :

$E=\dfrac{1}{2}kx^2$

$E=\dfrac{1}{2}\times 5.2\times (1.12)^2$

E = 3.26 J

So, the elastic potential energy stored in the spring is 3.26 joules.

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3 years ago