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KiRa [710]
3 years ago
13

Electric eels generate electric pulses along their skin that can stun an enemy. In a test, an electric eel generated pulse of 50

0 V that produced a current of 80 mA for 10ms. Assuming a steady current, what was the power of the pulse?
A. 63 W
B. 16 W
C. 40 W
D.59 W
Physics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

The power of the pulse is 40 Watts

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The work done by the pushing force is 200 J; option B.

<h3>What is work done in an inclined plane?</h3>

The work done in an inclined plane is given by the formula below:

  • Work done = Force * distance

Force, F = mgsinθ + ma

where a = 0

Work done = 80 * 5 * sin 30°

Work done = 200 J

In conclusion, work done is the product of force and distance.

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Which element most likely has a shiny luster​
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Answer:

Rhodium. This extremely rare, valuable and silvery-colored metal is commonly used for its reflective properties. ...

Platinum.

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Iridium.

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Explanation:

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3 years ago
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The table represents the forces on four objects, with directions. Object F1 ↑ F2 → F3 ← F4 ↓ W 30 N 20 N 20 N 30 N X 15 N 35 N 2
Reika [66]

When the magnitude of all opposing forces is equal, then the force is called balanced. The forces on W and Y are balanced while the forces on X and Z are unbalanced.

<h2>Net Force:</h2>

It is defined as the vector sum of all forces acting on the object. The forces with the same magnitude in the opposite direction cancel each other.

<h3>Balanced force: </h3>

When the magnitude of all opposing forces is equal, then the force is called balanced.

<h3>Unbalanced force: </h3>

When a force is more than the opposing force, the force is called unbalanced.

Therefore, the forces on W and Y are balanced while the forces on X and Z are unbalanced.

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5 0
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Which section (A or B) of the roller coaster shows positive acceleration?
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It is (A) for the first one and (B) for the second one.

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4 years ago
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A 1.0-in.-diameter hole is drilled on the centerline of a long, flat steel bar that is 1 2 thick and 4 in. wide. The bar is subj
Dominik [7]

Answer:

The answers are

The average stress = 20000 lb/in²

The maximum tensile stress immediately adjacent to the hole

= 31076.92 lb/in²

Explanation:

To solve the question we have

Weight of tensile load = 30,000 lb

Width of steel bar = 4 in

Thickness of steel bar = 1/2 in

Average Stress = Force/Area  

Size of hole drilled = 1.0 in diameter

Available width at cross section where the 1.00 in diameter hole is drilled =

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Cross sectional area at the point of reduced cross section due to the drilled hole = Width × Thickness (Since the item is a flat bar)

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