The answer should be -7°. What I did was just subtract 7 for each day. Im pretty sure there is a faster way, but this is how I did it
Answer:
There are 199 pairs of consecutive natural numbers whose product is less than 40000.
Step-by-step explanation:
We notice that such statement can be translated into this inequation:
Now we solve this inequation to the highest value of 
that satisfy the inequation:
The Quadratic Formula shows that roots are:
Only the first root is valid source to determine the highest possible value of , which is 
. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.
12.6803 would be the answer hope you get your homework/quiz 100%
We have that
<span>sin x=2/9
we know that
sin</span>² x+cos² x=1---------> cos² x=1-sin² x-----> cos² x=1-(2/9)²
cos² x=1-(4/81)------> (81-4)/81-----> 77/81
cos x=√(77/81)
Sin 2x = 2 sin x cos x-------> 2*(2/9)*(√(77/81))----> (4/81)*√77---> 0.43
Sin 2x=0.43
so
cos² 2x=1-sin² 2x---------> 1-[0.43]²-----> 1-[0.1878]----> 0.81
cos² 2x=0.81-----------> cos 2x=0.9
tan 2x=sin 2x/cos 2x--------> tan 2x=0.43/0.9---------> tan 2x=0.48
the answers are
sin 2x=0.43
cos 2x=0.9
tan 2x=0.48
heck nah
Step-by-step explanation:
heck nah
