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kondor19780726 [428]
2 years ago
9

The graph shows the functions f(x), p(x), and g(x):

Mathematics
1 answer:
Zinaida [17]2 years ago
3 0
A) The solutions to this set of equation is where the graphs cross. They cross at point (-3, -2).

B) The solutions for f(x) would be points that fall on the graph of f(x). Two possible points are (-3, -2) and (-7, 3)

C) These 2 functions cross at (4, 1). That is the solution.
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Directions for (1-5): Plot the following on a number line<br> 0.75<br> 1.5<br> -2 ¾<br> -3 ⅕<br> 6.8
lana [24]

Answer:

|---|--------|---------|------|---------|-|

-2 ¾   -3 ⅕    0.75  1.5       6.8

(This is a rough answer, it mainly just shows the order).

Step-by-step explanation:

1. -2 ¾

2. -3 ⅕

3. 0.75

4. 1.5

5. 6.8

7 0
2 years ago
. A retailer buys pants at $22.00 and sells them for $26.40 The percent of markup on cost is 50 percent. 13 percent. 20 percent.
lana [24]
22     = 100%
26,40 = x%

26,4*100/22=120%
x=120%

120%-100%=20%
The answer is 20%
8 0
3 years ago
Which expression is equivalent to (5x^3)(2x)^3
Taya2010 [7]
Hello:
(5x^3)(2x)^3 = (5x^3)(2)^3(x)^3 = <span>(5x^3)8x^3=40x^6  ... (answer C)</span>
3 0
3 years ago
Read 2 more answers
If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is -1, then what will be the product of the other two zeros?
zhenek [66]

Answer:

The product of the other two zeros is c

Step-by-step explanation:

Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:

sum of the roots = α + β + γ = -a

-1 + β + γ = -a

β + γ = -a + 1

αβ + αγ + βγ = b

-1(β) + (-1)γ + βγ = b

-β -γ + βγ = b

Also, the product of the zeros is equal to -c, hence:

αβγ = -c

-1(βγ) = -c

βγ = c

Hence the product of the other two zeros is c

6 0
3 years ago
If the product of two number is 10 and the sum is 7 ,then the longest of the two number is​
irinina [24]

Answer:

5 units

Step-by-step explanation:

Step one:

Given data

Le the first number be x

and the second number be y

So

x*y= 10-----------------1

and

x+y= 7-----------------2

from eqn 1

x= 10/y

put x= 10/y in eqn 2

10/y+y= 7\\\\10/y= 7-y

cross multiply we have

10=y(7-y)\\\\10=7y-y^2

rearrange

y^2-7y+10=0

the factors of the quadratic expression are

-5 and -2

y^2-5y-2y+10= 0\\\\y(y-5)-2(y-5) =0\\\\y-2=0\\\\y= 2\\\\y-5= 0\\\\y=5\\\\

The longest side is 5 units

3 0
2 years ago
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