The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
brainly.com/question/10633821
#SPJ4
Answer:
becauz the cos .1sj sin A the thing cos
Answer:y=2/3x-10/3
- 4/-6 is 4/6 so m is 4/6 then fill in the x and y variables in y=Mx+b solve for b then start plotting the equation of the line to check and you get your answer
I think this is the answer you might need to check again with more people
Answer:
its B because
Step-by-step explanation:
Simplifying
41n(7x) = 8
Remove parenthesis around (7x)
41n * 7x = 8
Reorder the terms for easier multiplication:
41 * 7n * x = 8
Multiply 41 * 7
287n * x = 8
Multiply n * x
287nx = 8
Solving
287nx = 8
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Divide each side by '287x'.
n = 0.02787456446x-1
Simplifying
n = 0.02787456446x-1
Answer:
x=7
Step-by-step explanation:
h(x) = 17 so you would input 17 for h(x). The equation should look like this. 17= 3x-4. Add 4 to both sides changing the equation to 21 = 3x. Finally divide both side by 3 and you should get x = 7.
