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klio [65]
2 years ago
13

Which of the following is correct equation for the trend line in the scatter plot? A. Y= 2/5 x -2 B. Y= 5x-1 C. Y= 5x +5 D. Y= -

x+5

Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

Answer: C. Y = 5x + 5

Step-by-step explanation:

    We need to write, or decide on, the equation for the blue line as this line represents the trend line for this scatter plot. We will write this in slope-intercept form. <em>See attached for a visual</em>.

    First, we will find our slope. We will use \frac{rise}{run} for this since we have a graph with clear points. See attached, we count up [5] and then count to the right [1] for a slope of 5.

     -> Slope = 5

   Now, we will find our y-intercept. This is where the line intersects the y-axis. The line hits the y-axis at point (0, 5) giving us a y-intercept of 5.

     -> Y-intercept = 5

   Lastly, we will write our equation and decide on an answer.

y = <em>m</em>x + <em>b</em>

y = (5)x + (5)

Y = 5x + 5

             C. Y = 5x + 5

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If the supplement of &lt;1 is 32º less than the measure of &lt;1, what is m&lt;1? a 1060 b 74o c 61o d 29o
rosijanka [135]

Answer:

a. 106 degrees

Step-by-step explanation:

m=measure of angle 1; m-32 degrees=measure of supplement

m+(m-32 degrees)=180 degrees Add 32 degrees to each side.

2m=212 degrees Divide each side by 2

m=106 degrees ANSWER: The measure of angle 1 is 106 degrees

 

CHECK:

106+(106-32)=180

106+74=180

180=180

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3 years ago
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Naya [18.7K]

Classwork:

Given f(x) = x^2 - 1 and g(x)=2x+5, we have

(1) (f\circ g)(x) = f(g(x)) = f(2x+5) = (2x+5)^2 - 1 = \boxed{4x^2+20x+24}

Using the composition found in (1), we have

(2) (f\circ g)(-2) = 4\cdot(-2)^2+20\cdot(-2)+24 = \boxed{0}

(3) (g\circ f)(x) = g(f(x)) = g(x^2-1) = 2(x^2-1) + 5 = \boxed{2x^2 + 3}

Using the composition found in (3),

(4) (g\circ f)(1) = 2\cdot1^2+3 = \boxed{5}

Homework:

Now if f(x)=x^2-3x+2, we would have

(1) (f\circ g)(x) = f(2x+5) = (2x+5)^2-3(2x+5)+2 = \boxed{4x^2+14x+12}

For (2), we could explicitly find (g\circ f)(x) then evaluate it at <em>x</em> = -1 like we did in the classwork section, but we don't need to.

(2) (g\circ f)(-1) = g(f(-1)) = g((-1)^2-3\cdot(-1)+2) = g(6) = 2\cdot6+5 = \boxed{17}

(3) We can demonstrate that both methods work here:

• by using the result from (1),

(f\circ g)(2) = 4\cdot2^2+14\cdot2+12 = \boxed{56}

• by evaluating the inner function at <em>x</em> = 2 first,

(f\circ g)(2) = f(g(2)) = f(2\cdot2+5) = f(9) = 9^2-3\cdot9+2 = \boxed{56}

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3 years ago
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Serggg [28]

Answer:

  • Lets consider the rectangle
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OLEGan [10]

Answer:

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Step-by-step explanation:

if ∠DAB =110 then ∠BAC =180-110 =70° because straighht lines make 180°∠s

use the fact that the sum of angles in a Δ is 180°

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