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never [62]
3 years ago
9

2(5x-7)=2x+10 what Is the distributive property

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:x = 3

Step-by-step explanation:

2(5x-7)=2x+10

distribute 2(5x-7)

=2*5x - 2*7

  ∨       ∨

  10x - 14

10x - 14 = 2x + 10

add 14 to both sides

10x-14=2x+10

    +14      +14

simplify

10x=2x+24

subtract 2x to both sides

10x=2x+24

-2x -2x

simplify

8x=24

divide both sides by 8

 8x=24

÷8x ÷ 8x

x = 3

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cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos(40^o)=\dfrac{20}{BD}\\\\\\BD=\dfrac{20}{cos(40^o)}\\\\\\BD=26.1

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Given the coordinates for the function below which of the following are coordinates for its inverse
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What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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