Craig ran 4 days last week. His distances were

1 answer:

8 0

6.875 average.

To calculate the average you add up all of the numbers and divide it by the number of numbers there are, in this case there are 4 numbers. So you add 3.25+6.5+7.25+10.5 and divide that by 4

You might be interested in

To measure the height of a tree, a surveyor walked a short distance from the tree and found the angle of elevation was 43.9°, th

padilas [110]

Answer:

The height of the tree is H = 77.06 m

Step-by-step explanation:

From Δ ABC

AB = height of the tree

$\tan 43.9 = \frac{AB}{BC}$

$\tan 43.9 = \frac{h}{x}$

h = 0.9623 x ------- (1)

From Δ ABD

$\tan 37.6 = \frac{h}{20+ x}$

h = 0.77 (x + 20) ----- (2)

Equating Equation 1 & 2 we get

0.9623 x = 0.77 (x + 20)

0.9623 x = 0.77 x + 15.4

x (0.1923) = 15.4

x = 80.08 m

Thus the height of the tree is given by

H = 0.9623 x

H = 0.9623 × 80.08

H = 77.06 m

Therefore the height of the tree is H = 77.06 m

4 0

3 years ago

F(x) = 2x^2 − 3x − 5 Part

riadik2000 [5.3K]

Answer: Answer is in the steps..

Step-by-step explanation:

f(x)= $2x^{2}$ - 3x -5

A) To find the x intercepts of a parabola we have to set the whole equation equal zero because the x intercept is when y equal zero in other words where f(x) equal zero.

$2x^{2}$ - 3x - 5 = 0 Now solve using quadratic formula.

x = -b± $\frac{\sqrt{b^2 -4ac } }{2a}$

x = 3 ± $\sqrt{9+40} /2a$

x = 3 ± $\sqrt{49}$ / 2a

x= 3 ± 7 /4

x= -1 or x = 5/2

The x intercepts are (5/2,0) and (-1,0)

B) The graph vertex of the graph of f(x) is going to be at a minimum because the leading coefficient of the function has a positive integer which means the parabola will open up and its vertex will be at the minimum point.

Using the x coordinates we could find their average and find the x coordinate of the vertex.

$\frac{5}{2} + -\frac{1}{1}$ = $\frac{3}{2} / \frac{2}{1}$ = 3/4