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ddd [48]
3 years ago
6

Consider the graph that represents the following quadratic equation y=-1/3(x+2)^2+5

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0
We have that

y=-1/3(x+2)²+5
using a graph tool
see the attached figure

we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0)  and (1.873,0)
5) the y intercept value is (0,3.667)

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Please help me!! I don't get this question! I will mark Brainliest!
TEA [102]

Answer:

Part A:

Formula for circumference: C = diameter x pi

=> pi = C/diameter

=> pi(A) = 12.56/4 =3.14

=> pi(B) = 6.28/2 = 3.14

Part B:

Formula for area: A = radius^2 x pi = (diameter/2)^2 x pi

=> pi = A/(diameter/2)^2

=> pi(A) = 12.56/(4/2)^2 = 12.56/4 = 3.14

=> pi(B) = 3.14/(2/2)^2 = 3.14/1 = 3.14

Part C:

pi(A) = pi(B) = 3.14 in both ways of calculation derived from circumstance and area.

=> pi is a constant value: 3.14

5 0
4 years ago
Read 2 more answers
Fourteen less than five times number is three times a number. Define a variable, write an equation, and solve to find the number
goldenfox [79]
5a-14=3a
-5a      -5a
-14= -2a
----    ----
-2       -2
<span>7=a

a is the variable, </span><span>5a-14=3a and a equals 7.</span>
8 0
3 years ago
Victoria wants to purchase a skate board . She has $125 to spend she finds one that regularly sells for $139.99 and is on a sale
zzz [600]

Answer:

no she wont. because the total cost of the skateboard will be 127.31

Step-by-step explanation:

6 0
3 years ago
Using a directrix of y = −3 and a focus of (2, 1), what quadratic function is created?
bazaltina [42]
<span>f(x) = one eighth (x - 2)^2 - 1
   Since a parabola is the curve such that all points on the curve have the same distance from the directrix as the distance from the point to the focus.With that in mind, we can quickly determine 3 points on the parabola. The 1st point will be midway between the focus and the directrix, So: (2, (1 + -3)/2) = (2, -2/2) = (2,-1). The other 2 points will have the same y-coordinate as the focus, but let offset on the x-axis by the distance from the focus to the directrix. Since the distance is (1 - -3) = 4, that means the other 2 points will be (2 - 4, 1) and (2 + 4, 1) which are (-2, 1) and (6, 1). The closest point to the focus will have the same x-coordinate as the focus, so the term will be (x-2)^2. This eliminates the functions "f(x) = -one eighth (x + 2)^2 - 1" and "f(x) = -one half (x + 2)^2 - 1" from consideration since their x term is incorrect, leaving only "f(x) = one eighth (x - 2)^2 - 1" and "f(x) = one half (x - 2)^2 + 1" as possible choices. Let's plug in the value 6 for x and see what y value we get from squaring (x-2)^2. So: (x-2)^2 (6-2)^2 = 4^2 = 16 Now which option is equal to 1? Is it one eighth of 16 minus 1, or one half of 16 plus 1? 16/8 - 1 = 2 - 1 = 1 16/2 + 1 = 8 + 1 = 9 Therefore the answer is "f(x) = one eighth (x - 2)^2 - 1"</span>
3 0
4 years ago
Read 2 more answers
Can someone please help me workout this problem? If the quotient obtained by dividing 8x^4 - 2x^2 + 6x - 7 by 2x+1 is equal to 4
Angelina_Jolie [31]

Answer:

The answer to your question is p = -2 q = -6  remainder = -10

Step-by-step explanation:

Data

Dividend = 8x⁴ - 2x² + 6x - 7

Divisor    = 2x + 1

Quotient = 4x³ + px² - qx + 3

Process

1.- Divide using long division

                                4x³ - 2x² + 3                          

                   2x + 1   8x⁴ + 0x³ - 2x² + 6x - 7

                             - 8x⁴ - 4x³

                                 0   - 4x³ - 2x²

                                      + 4x³ +2x²

                                          0       0   + 6x - 7

                                                          -6x - 3

                                                             0 - 10    Remainder

         px² = -2x²  then  p = -2

         -qx = 6x     then q = -6

5 0
3 years ago
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