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ddd [48]
4 years ago
6

Consider the graph that represents the following quadratic equation y=-1/3(x+2)^2+5

Mathematics
1 answer:
weqwewe [10]4 years ago
8 0
We have that

y=-1/3(x+2)²+5
using a graph tool
see the attached figure

we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0)  and (1.873,0)
5) the y intercept value is (0,3.667)

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Levart [38]

Answer:

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Step-by-step explanation:

equation of a circle:  (x - h)^2+(y-k)^2=r^2

where (h, k) = center and r = radius

From inspection, we can see that the center of the circle = (0, 0)

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\implies x=\pm \sqrt{\frac{1}{4}}

\implies x=\pm\frac{1}{2}

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