Consider the graph that represents the following quadratic equation y=-1/3(x+2)^2+5
1 answer:
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Given:
ΔONP and ΔMNL.
To find:
The method and additional information that will prove ΔONP and ΔMNL similar by the AA similarity postulate?
Solution:
According to AA similarity postulate, two triangles are similar if their two corresponding angles are congruent.
In ΔONP and ΔMNL,
(Vertically opposite angles)
To prove ΔONP and ΔMNL similar by the AA similarity postulate, we need one more pair of corresponding congruent angles.
Using a rigid transformation, we can prove
Since two corresponding angles are congruent in ΔONP and ΔMNL, therefore,
(AA postulate)
Therefore, the correct option is A.
Answer:
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers at most =30/60=0.5
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Step-by-step explanation:
Relative Frequency Frequency x
6/60=0.1 6 0
0.2 12 1
0.2 12 2
0.25 15 3
0.1 6 4
0.05 3 5
0.05 3 6
0.0167 1 7
<u>0.033 2 8</u>
<u>∑ 60 </u>
The number of six non conforming transducers at most
= 6+12+12+15+6+3= 54
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than five non conforming transducers
= 6+12+12+15+6 = 51
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers
2+1+3+3+6+15= 30
The number of at least six non conforming transducers at most =30/60=0.5
We plot the histogram by placing the percentages (or relative frequency *100) on the y –axis and the X on the x-axis.
The center of the histogram is given by the mean of the distribution which in this case is = ∑fx/∑f= 161/60= 2.683
So option d is the best answer
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Because at the center (between 2 and 3) the curve is increasing
