Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
The graph of y > mx, where m > 0, consists of a dashed line and a shaded half plane. The line has a positive slope and passes through the origin. The shaded half plane is above the line.
Answer: Irrational
Step-by-step explanation:
It is irrational because you cannot multiply a number by the same number to get the square root of 2.
I think the approximation is 1.4 or 1.42
3 1/2r=28
3.5r=28
cross of 3.5 and r remains
divide 28 and 3.5
and r=8
r=8
3d - e = 7d + e = 5 ⇒ 3d - e = 5
7d + e = 5
3d - e = 5
7d + e = 5 +
-----------------------
10d / = 10
10d = 10
d = 10/10
d = 1
7d + e = 5
7×1 + e = 5
7 + e = 5
e = 5 - 7
e = -2