8ktar=r-2y solve for r

1 answer:

3 0

$8ktar=r-2y\ \ \ |-r\\\\8ktar-r=-2y\\\\r(8kta-1)=-2y\ \ \ |:(8kta-1)\neq0\\\\r=\dfrac{-2y}{8kta-1}\to r=\dfrac{2y}{1-8kta}$

Example from comment:

$8k+ar=r-2y\ \ \ |-8k\\\\ar=r-2y-8k\ \ \ |-r\\\\ar-r=-2y-8k\\\\r(a-1)=-2y-8k\ \ \ |:(a-1)\neq0\\\\r=\dfrac{-2y-8k}{a-1}\to r=\dfrac{-(2y+8k)}{-(1-a)}\to r=\dfrac{2y+8k}{1-a}$

You might be interested in

How Can I find ef? Do I multiply add or diving

Solnce55 [7]

$\bf \stackrel{eg}{5x+8}-\stackrel{fg}{3x}=\stackrel{ef}{6x-4}\implies2x+8=6x-4\implies 12=4x
\\\\\\
\cfrac{12}{4}=x\implies 3=x\qquad \qquad \stackrel{ef}{6(3)-4}$

and surely you know how much that is.

6 0

3 years ago

(I’ll give brainilest) help asap

Gekata [30.6K]

Answer:

option c: y=9x+0.5

that's the answer!

4 0

3 years ago

What is the answer for part b

trasher [3.6K]

Answer:

(-3,-10)

Step-by-step explanation:

Given part a, you seem to know the midpoint formula. We can easily edit that to figure out what an endpoint is. Say that a variable "a" represents the x coordinate of D, and b the y coordinate. As the x coordinate of M is 0.5, and the x coordinate of C is 2, we can use the midpoint formula to say that $\frac{a+2}{2} =-0.5$ . Multiplying both side by 2, we get that a+2=-1, and subtracting both sides by 2, a=-3. Similarly, $\frac{b+7}{2} =-1.5$ , b+7=-3, and b=-10, making our answer (-3, -10). Let me know if you have any questions.