All categories

3 years ago

8ktar=r-2y solve for r

1 answer:

3 0

$8ktar=r-2y\ \ \ |-r\\\\8ktar-r=-2y\\\\r(8kta-1)=-2y\ \ \ |:(8kta-1)\neq0\\\\r=\dfrac{-2y}{8kta-1}\to r=\dfrac{2y}{1-8kta}$

Example from comment:

$8k+ar=r-2y\ \ \ |-8k\\\\ar=r-2y-8k\ \ \ |-r\\\\ar-r=-2y-8k\\\\r(a-1)=-2y-8k\ \ \ |:(a-1)\neq0\\\\r=\dfrac{-2y-8k}{a-1}\to r=\dfrac{-(2y+8k)}{-(1-a)}\to r=\dfrac{2y+8k}{1-a}$

You might be interested in

A pet store sells dog food in a 3-pound bag for $12.00 and a 5-pound bag for $14.25. Which bag of dog food is the better buy? Ex

Bess [88]

The 5-pound bag is better value.

The easiest way to compare and find out which is a better buy is to find out how much is being charged for 1-pound of food in each bag.

$12 is divided by 3 beacuse it's a 3-pound bag and we are aiming to find what 1-pound is equal to.

$12 ÷ 3 = $4

So the first bag charges $4 per pound of food.

Then use the same method for the 5-pound bag.

$14.25 ÷ 5 = $2.85

So the second charges $2.85 per pound of food.

So as we can see, the 5-pound bag is clearly better value. For each pound of food you are saving $1.15 in comparison to what you would be spending if you opted for the first bag.

Hope this helps!

5 0

3 years ago

In need of some help! Thank you in advance. 100 points <3

Anni [7]

Answer:

the equation (x-4)^2-17=8 has two solutions because it is in a quadratic form.

(x-4)^2-17=8

x²-8x+16-17-8=0

x²-8x-9=0

Doing middle term factorization

x²-9x+x-9=0

x(x-9)+1(x-9)=0

(x-9)(x+1)=0

either

x=9

x=9or

x=9orx=-1

x^2+4x+3=0:

Doing middle term factorization

x²+3x+x+3=0

x(x+3)+1(x+3)=0

(x+3)(x+1)=0

either

x=-3

x=-1

Josh’s solution is incorrect because he missed x=-3.

3.

x^2-6x+7=0

By using quadratic equation formula:

Comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=7

Now

we have

x= $\frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

x= $\frac{ 6± \sqrt{ {-6}^{2} - 4*1*7} }{2}$

x= $\frac{ 6±2\sqrt{ 2}}{2}$

x= ${ 3±\sqrt{ 2}}$

Taking positive

x= ${ 3+\sqrt{ 2}}$

taking negative

x= ${ 3-\sqrt{ 2}}$

4 0

3 years ago

How do i solve 3x-5y=9;x=-1,0,1

REY [17]

For x = -1, 3(-1) - 5y = 9 => -3 - 5y = 9 => 5y = -3 - 9 = -12 => y = -12/5 = -2.4
for x = 0, 3(0) - 5y = 9 => -5y = 9 => y = 9/-5 = -1.8
for x = 1, 3(1) - 5y = 9 => 3 - 5y = 9 => 5y = 3 - 9 = -6 => y = -6/5 = -1.2

7 0

3 years ago

Whats number 7?? im so confused!!

I am Lyosha [343]

Maybe D? I'm not exactly sure, I'm sorry

7 0

3 years ago

What is three fourths divided by eight thirdteenths?

xz_007 [3.2K]

$\frac{3}{4} , \frac{8}{13}$ is $\frac{39}{32}$

$\frac{3}{4} * \frac{13}{8} = ?$ , multiple by the reciprocal of the second fraction to get the answer.

3 0

3 years ago