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Lyrx [107]
3 years ago
13

8ktar=r-2y solve for r

Mathematics
1 answer:
NARA [144]3 years ago
3 0

8ktar=r-2y\ \ \ |-r\\\\8ktar-r=-2y\\\\r(8kta-1)=-2y\ \ \ |:(8kta-1)\neq0\\\\r=\dfrac{-2y}{8kta-1}\to r=\dfrac{2y}{1-8kta}

Example from comment:

8k+ar=r-2y\ \ \ |-8k\\\\ar=r-2y-8k\ \ \ |-r\\\\ar-r=-2y-8k\\\\r(a-1)=-2y-8k\ \ \ |:(a-1)\neq0\\\\r=\dfrac{-2y-8k}{a-1}\to r=\dfrac{-(2y+8k)}{-(1-a)}\to r=\dfrac{2y+8k}{1-a}

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Answer:

B and C work. A and D do not.

Step-by-step explanation:

This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.

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B

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========

C

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