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natka813 [3]
3 years ago
13

Lilly’s car uses 5 gallons of gas to drive 230 miles. At what rate does her car use gas in gallons per mile?

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

0.02 gallons per mile, and 46 miles per gallon.

Step-by-step explanation:


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Which of the following values in the set below will make the equation 2x + 1 = 3 true? (Only input the number.)
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The only one that makes sense is 1
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1+4=5 2+5=12 3+6=21 what is 8+11=
BlackZzzverrR [31]
8+11 is 19 Hope it helped
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The answer should look like this. (___,___) plzzz fast. ​
BartSMP [9]

Answer:

( -1, 15/2) or ( -1, 7 1/2)

Step-by-step explanation:

Formula: ( (x1 + x2)/2, (y1 + y2)/2 )

1. ( (-4 +6)/2, (8 + 7)/2 ) Plug in

2. ( -2/2, 15/2) Add/Subtract

3. ( -1, 15/2) or ( -1, 7 1/2) Divide

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How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
3 years ago
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