The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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The answer would be 7 cups....... if it’s wrong I would recommend you to use Brainfuse
<h3>Answer: Choice A) 24.0</h3>
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Explanation:
Let's say we had a triangle with side lengths a,b,c.
If we know that a = 12.25 and b = 12.25, then the third side c has its length restricted in such a way that
b-a < c < b+a
This is a variation of the triangle inequality theorem.
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So,
b - a < c < b + a
12.25 - 12.25 < c < 12.25 + 12.25
0 < c < 24.5
which means the third side c is between 0 inches and 24.5 inches.
The value of c cannot be 0, and it cannot be 24.5 either.
Among the answer choices given, we see that only 24.0 is the only valid option here. The other two choices are too large.
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Side Note: If your teacher gave you two angles (instead of two sides) to be 12.25 degrees, and wanted the third missing angle of the triangle, then you would be correct in having 12.25+12.25+x = 180 as your first step.
