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3 years ago

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Explain how subshells are related to electrons, and describe the size of each subshell.

1 answer:

PilotLPTM [1.2K]3 years ago

8 0

Answer & Explanation:

Orbitals are made up of subshells- s, p, d, f.

Each subshell can only accommodate a certain number of electrons:

s- 2 electrons

p- 6 electrons

d- 10 electrons

f- 14 electrons.

The subshells are used to denote the element by spelling out its electronic configuration.

Hope this was helpful!

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Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

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2 years ago

A 0.73 m solution of chloroacetic acid, , has a ph of 1.50. calculate for the acid.

erik [133]

PH = 0.1289<span> for </span>1.50<span> M solution of weak acid with Ka value of </span><span>.73</span>

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Answer:

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Explanation:

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3 years ago

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xxTIMURxx [149]

<span>d)S is not one of them.

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2 years ago

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What type of reaction is shown below c10H8+12O2 10co2+4H2O

MakcuM [25]

Answer:

Explanation:

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