Answer:
0.00915 M of remain after 5.16 seconds.
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given that:
The rate constant, k = s⁻¹
Initial concentration = 0.054 M
Final concentration = ? M
Time = 5.16 s
Applying in the above equation, we get that:-
<u>0.00915 M of remain after 5.16 seconds.</u>
Answer: The value of is 0.0057
Explanation:
Initial moles of = 0.900 mole
Volume of container = 2.00 L
Initial concentration of
equilibrium concentration of [/tex]
The given balanced equilibrium reaction is,
Initial conc. 0.450 M 0 0
At eqm. conc. (0.450 -2x) M (2x) M (x) M
The expression for equilibrium constant for this reaction will be,
we are given : x = 0.055
Now put all the given values in this expression, we get :
Thus the value of the equilibrium constant is 0.0057