Recall that tanA = sinA / cosA.
Therefore, tanA = (3/5) / (4/5) = 3/4.
Answer:
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<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let


<h3>Hence, A can't be Pythagoras triplet</h3>
2) a² + b² = c²


<h3>Therefore, B can be Pythagoras triplet</h3>
3)a² + b² = c²


<h3>Hence, C can't be Pythagoras triplet</h3>
4) a² + b² = c²


<h3>Hence, D can't be Pythagoras triplet</h3>
<h2 /><h2>Therefore :-</h2>
Only B can be Pythagoras triplet.
What are you trying to solve i can't see anything
A. because the lease amount of negative is actually more. if that makes any sense