Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
0.87 > 0.17
3.97 < 6.63
8.04 < 8.9
Is that what ur looking for?
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u>Use identities to set the equation up as a quadratic</u>

<u>Make the substitution u=cos(x) and solve the quadratic</u>
<u />


Hence, 
Answer:
55 mph
Step-by-step explanation:
We see that CF and DE are parallel to each other, which means that they had the same length with each other, so:
6n-1=5n+9
Subtract 5n for both side
6n-1-5n=5n+9-5n
n-1=9
Add 1 for both side
n-1+1=9+1
n=10
CF=
6n-1
=6(10)-1
=60-1
=59
DE=
5n+9
=5(10)+9
=50+9
=59
CD/FE:
4n+2
=4(10)+2
=42
True/False:
n=10 True
n=7 False
CF=59 True
FE=42 True
CD=30 False. As a result, n=10;CF=59; and FE=42 is your final answer. Hope it help!