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scoundrel [369]
3 years ago
11

What is 22% expressed as a fraction in simplest form?

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0
<span>22% when expressed as a fraction is 22/100.
 to write this in the simplest form, we have to keep dividing both numerator and denominator by a common number.
22/100 , both are divisible by 2. therefore when 22/100 is divided by 2
</span>\frac{22/2}{100/2} =  \frac{11}{50}<span>
then we get 11/50. this cannot be divided any further by a common factor to both. therefore simplest form is 11/50</span>
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X + y = -1<br> 4x - 2y = -16
djyliett [7]

Answer:

x=-3 \\and\\ y=2

Step-by-step explanation:

x + y = -1       Equation:1

4x - 2y = -16    Equation:2

Solving Equation:1

x+y=-1

Subtracting 'y' from both the sides:

x+y-y=-1-y\\\\x=-1-y

Putting 'x' in Equation :2

       4(-1-y)-2y=-16\\\\-4-4y-2y=-16\\\\-4-6y=-16

Adding '4' both the sides

          -6y=-16+4\\\\-6y=-12\\\\y=-12/-6\\\\y=2

Putting the value of 'y' in equation:1

           x+y=-1

           x+(2)=-1\\\\x=-1-2\\\\x=-3\\

The solution is:

          x=-3 \\and\\ y=2

6 0
2 years ago
-3x=x-(6-2x) explain how asap, please!!
OLEGan [10]
Answer: x=1
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-6x=-6
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7 0
2 years ago
Emma had 10 Balls in a bag. The balls were numbers 1 through 10. She wanted to test the probability of drawing a ball that is a
Goryan [66]

Answer:

  • 30%
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Step-by-step explanation:

<u>The balls - multiples of 3 are:</u>

  • 3, 6 and 9

<u>The probability of a multiple of 3 is:</u>

  • 3 out of 10 or
  • P = 3/10 = 30%

30% probability is in the range 0%-50% so this event is unlikely

5 0
3 years ago
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What’s the quotient of 20 and 2
olasank [31]

the answer is 10 hoped this helped have a great day


5 0
3 years ago
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7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t
Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

\frac{x^a}{x^b}=x^{a-b}

x^0=1

(x^a)(x^b)=x^{a+b}

x^{-a}=\frac{1}{x^a}


\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=

\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=

\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=

(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=

(7^{-5-(-5)})(2^{0-3})=

(7^0)(2^{-3})=

\frac{1}{2^3}=

\frac{1}{8}

7 0
3 years ago
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