Ask question

Ask question

All categories

andrew-mc [135]

2 years ago

8

Write an equation showing the relationship between the number of baskets (b) made from outside the three-point line and the numb

er of points scored (p).

2 answers:

monitta2 years ago

8 0

P=3b
P(points scored) 3(three point line) B(baskets)

Scorpion4ik [409]2 years ago

4 0

P=3b

p is the total number of points scored. Since there are 3 points being scored, you multiply that by the number of baskets made, b.

You might be interested in

Y = (x + 3)(x + 1)<br> Graph

irga5000 [103]

Answer:

Y= 4x...Hope this helps!

Step-by-step explanation:

7 0

3 years ago

Use the Polygon tool to draw an image of the given polygon under a dilation with a scale factor of 13 and center of dilation at

Stells [14]

Answer:

a

adf

Step-by-step explanation:

a

7 0

3 years ago

The point J(5,3) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, J'

Masja [62]

Answer;

J(5,3) = x,y

rotated on 90;

J'(-3,5)

Therefore, the coordinates of the resulting point is J'(-3,5).

6 0

2 years ago

Simplify completely quantity 5 x squared minus 21 x minus 20 all over quantity 5 x squared minus 16 x minus 16.

Morgarella [4.7K]

(5x^2-21x-20)/(5x^2-16x-16)
((x-5)(5x+4))/((x-4)(5x+4))
(x-5)/(x-4)

8 0

4 years ago

Read 2 more answers

Write an equation in standard form of the line passing through points

Aneli [31]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -\frac{4}{9} &,& \frac{4}{9}~) 
% (c,d)
&&(~ \frac{6}{5} &,& \frac{4}{5}~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{\frac{4}{5}-\frac{4}{9}}{\frac{6}{5}-\left( -\frac{4}{9} \right)}\implies \cfrac{\frac{4}{5}-\frac{4}{9}}{\frac{6}{5}+\frac{4}{9}}$

$\bf \cfrac{\quad \frac{36-20}{45}\quad }{\frac{54+20}{45}}\implies \cfrac{\quad\frac{16}{45} \quad }{\frac{74}{45}}\implies \cfrac{16}{45}\cdot \cfrac{45}{74}\implies \cfrac{16}{74}\implies \cfrac{8}{37}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-\cfrac{4}{9}=\cfrac{8}{37}\left[ x -\left( -\cfrac{4}{9} \right)\right]$

$\bf y-\cfrac{4}{9}=\cfrac{8}{37}\left( x +\cfrac{4}{9} \right)\implies y-\cfrac{4}{9}=\cfrac{8}{37}x+\cfrac{32}{333}
\\\\\\
y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{4}{9}\implies y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{148}{333}\implies y=\cfrac{8}{37}x+\cfrac{180}{333}
\\\\\\
y=\cfrac{8}{37}x+\cfrac{20}{37}\implies \stackrel{standard~form}{-\cfrac{8}{37}x+y=\cfrac{20}{37}}$

7 0

4 years ago