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andrew-mc [135]

2 years ago

8

Write an equation showing the relationship between the number of baskets (b) made from outside the three-point line and the numb

er of points scored (p).

2 answers:

monitta2 years ago

8 0

P=3b
P(points scored) 3(three point line) B(baskets)

Scorpion4ik [409]2 years ago

4 0

P=3b

p is the total number of points scored. Since there are 3 points being scored, you multiply that by the number of baskets made, b.

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How to do this , PLEASE HELP

Oksana_A [137]

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x^{123} x_{123} \sqrt[n]{x} \sqrt[n]{x} x_{123} \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx =1$

7 0

3 years ago

I need help ASAP please (radical expressions)

amid [387]

Answer:

A. I only

Step-by-step explanation:

We need to start off by <u>taking perfect squares out of these square roots.</u>

Begin with the numerator. It looks like we can take 4 out of the radical: $\sqrt{40} = \sqrt{4*10} = \sqrt{4} * \sqrt{10} = 2 \sqrt{10}$ <u />

Now we have

$\frac{2\sqrt{10}}{\sqrt{10} }$

Looks like those $\sqrt{10}$ s can cancel!

= 2

Plug those answers into your calculator. II and III don't equal 2, but I does. This makes sense when we consider the rule that if you're dividing two radicals, you can just pull the radical over the whole expression!

The answer is <u>A. I only.</u>

7 0

4 years ago

Sun-Yi estimated 270+146and got 300.is her estimate reasonable explain

Feliz [49]

No. Round 146 to 150 and add both 270 and 150. It's 420. So 400 would be more reasonable. 300 is not reasonable because it ain't close.

3 0

3 years ago

A machine is shut down for repairs if a random sample of 100 items selected from the daily output of the machine reveals at leas

Harlamova29_29 [7]

Answer:

0.7995 = 79.95% probability that the sample will contain at least three defectives.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Suppose that a random sample of 20 items is selected from the machine.

This means that $n = 20$

The machine produces 20% defectives

This means that $p = 0.2$

Mean and standard deviation:

$\mu = E(X) = np = 20*0.2 = 4$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.2*0.8} = 1.79$

Probability that the sample will contain at least three defectives

Using continuity correction, this is $P(X \geq 3 - 0.5) = P(X \geq 2.5)$ , which is 1 subtracted by the pvalue of Z when X = 2.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2.5 - 4}{1.79}$

$Z = -0.84$

$Z = -0.84$ has a pvalue of 0.2005

1 - 0.2005 = 0.7995

0.7995 = 79.95% probability that the sample will contain at least three defectives.

4 0

3 years ago

Find the volume of the solid generated by revolving the area bounded by y=x^2 and x-axis from [0,2] around the x-axis

lesya [120]

Answer: $\dfrac{32\pi }{5}\ \text{unit}^3$

Step-by-step explanation:

Given

The area is bounded by $y=x^2$ and x-axis from [0,2]

The volume generated for $y=f(x)$ when rotated about the x-axis in the interval [a,b] is

$V=\int_a^b\pi y^2dx$

Insert the values

$\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3$

8 0

3 years ago