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andrew-mc [135]

1 year ago

8

Write an equation showing the relationship between the number of baskets (b) made from outside the three-point line and the numb

er of points scored (p).

2 answers:

monitta1 year ago

8 0

P=3b
P(points scored) 3(three point line) B(baskets)

Scorpion4ik [409]1 year ago

4 0

P=3b

p is the total number of points scored. Since there are 3 points being scored, you multiply that by the number of baskets made, b.

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LiRa [457]

22 rides would be needed Explanation: one ride takes 6 kids and there are 130 kids 20 rides would take 120 21 rides would take 126 and since you can’t have kids without a ride and you can’t cut a ride into pieces there must be 22 rides

3 0

2 years ago

Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms

artcher [175]

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

6 0

3 years ago

A sweater was on sale at 40% off the regular price. Ella saved 20$ by buying the sweater on sale. What was the regular price of

barxatty [35]

Answer:

the answer is $50 for the full price of the sweater

Step-by-step explanation:

if you know $20 is 40% what is 20% it is $10 and then multiple it by 5 because 20 times 5 is 100 and you get 50

8 0

2 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

2 years ago

What is 64 times 10?

Tom [10]

64 x 10 = 640

Easier way to simplify :

64 x 1 = 64 and then put the 0 at the end which = 640

4 0

3 years ago

Read 2 more answers