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Inga [223]
3 years ago
14

A club with nineteen members is to choose three​ officers: ​ president, vice-president, and​ secretary-treasurer. If each office

is to be held by one person and no person can hold more than one​ office, in how many ways can those offices be​ filled?
Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

5,814

Step-by-step explanation:

19 × 18 × 17

5,814

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4. Divide, using synthetic division: 16x^3 +80x^2+x+5/x+5
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Answer:

Step-by-step explanation:

x+5=0

x=-5

-5) 16   80   1    5

  |       -80   0  -5

 ____________

  | 16    0    1  | 0

quotient=16x²+1

Remainder=0

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What GPA do you need to pass 8th grade
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2.0/4.0

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Suppose that 80% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
Gwar [14]

Answer:

P=0.147

Step-by-step explanation:

As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2

We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) .  To find the required probability 3 mentioned probabilitie have to be summarized.

So P(9/16 )=  C16 9 * P(good brakes)^9*Q(bad brakes)^7

P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02

P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007

P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12

P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147

7 0
2 years ago
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