(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
2.6/1.3 * 10^(9-2) = 2*10^7
Answer:x=7 y=5
Step-by-step explanation:
I just took it, sorry I'm not good at math and just guessed until I got it right for this answer.
Its y=3/4x+3
you can solve it
-3x+4y=12
add 3x both sides
4y=3x+12
divide 4 by both sides
y=3/4x+4
<span>x^2+6x+11=0
After solving this u will bet
X=-6+,-</span>√-8/2
So roots of a equation are imaginary