A standard number cube has 6 sides....
probability of rolling a 5 is 1/6......probability of not rolling a 5 is 5/6
Answer:
See explanation below.
The selection of drop down arrows from top to bottom should be:
5; 4; 1; 2; 3
Step-by-step explanation:
Quadrilateral with exactly ONE set of parallel sides: Trapezoid (option 5)
Parallelogram with 4 congruent (equal) sides and 4 right angles: square (option 4)
Quadrilateral with 2 pairs of parallel sides (notice no reference to angles between sides and constrain about similarity in side length - so this os the most general description): parallelogram (option 1)
Parallelogram with 4 right angles (notice no constrain about the length of the sides): rectangle (option 2)
Parallelogram with 4 congruent sides (notice there is no constrain about the angles between the sides): rhombus (option 3)
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:

So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.
Answer:

Step-by-step explanation:
difference in x = 7
difference in y = -30
using Pythagoras, distance =
=
= 
(but I don't understand what the nearest tenth part means)
Here are some prime numbers:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199