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2 years ago

Imagine you want to create a model of Solar system (and beyond) with the Sun

Physics

1 answer:

kondaur [170]2 years ago

5 0

Using the scale model of the Sun given;

The diameter of the Milky Way = 4.28 × 10¹¹ m
The diameter of the Earth = 5.44 × 10⁻³ m

<h3>What is the diameter of the Milky Way?</h3>

The diameter of the Milky Way is about 1 × 10¹⁸ km.

The diameter of the Sun is about 1.4 × 10⁶ km

The diameter of the Earth is about 1.27 × 10⁴ km.

Using the scale model of the Sun given, the diameter of the Milky Way = (1 × 10¹⁸ km/1.4 × 10⁶ km) × 0.6 m

The diameter of the Milky Way = 4.28 × 10¹¹ m

Using the scale model of the Sun given, the diameter of the Milky Way = (1.27 × 10⁴ km/1.4 × 10⁶ km) × 0.6 m

The diameter of the Earth = 5.44 × 10⁻³ m

In conclusion, the diameter of the Milky Way is far bigger than the Sun while the diameter of the Sun is about 5400 times bigger than the Earth.

Learn more about the Milky Way, Sun, and Earth at: brainly.com/question/1995133

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The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average,

3241004551 [841]

Answer:

For Pentium 4 Prescott:

% of Static Power = 10

For core i5 Ivy Bridge:

% of Static Power = 43

Given Information:

Static Power of P4 = 10 W

Dynamic Power of P4 = 90 W

Static Power of i5 = 30 W

Dynamic Power of i5 = 40 W

Required Information:

% of static power w.r.t total power dissipation = ?

Explanation:

For Pentium 4 Prescott:

% of static power = static power/total power * 100

% of static power = 10/(10 + 90) * 100

% of static power = 10/(100) * 100

% of static power = 10

For core i5 Ivy Bridge:

% of static power = static power/total power * 100

% of static power = 30/(30 + 40) * 100

% of static power = 30/(70) * 100

% of static power = 43 (rounded to nearest whole integer)

5 0

4 years ago

In 1 km races, runner 1 on track 1 (with time 2 min, 28.13 s) appears to be faster than runner 2 on track 2 (2 min, 28.48 s). ho

Murrr4er [49]

We are given with a velocity-distance-time kinematic problem given the different times of two runners and is asked for the difference in distances the runner has ran in the track. we use the formula v= d/t where d is the distance of running, t is time and v is the velocity of the runner.

First runner,
v = d/t = 1000 m / (120+28.13s ) = 6.750826976 m/s
Second runner
Using the same velocity we determine d2.
v = d2/t2 = d2 / (120+28.48s) = 6.750826976 m/s ; d2 = 1002.362789

distance of running track is the difference of the two distance achieved by the runners, delta d= d2 - d = 2.362789 m

3 0

3 years ago

Samantha is refinishing her rusty wheelbarrow. She moves her sandpaper back and forth 45 times over a rusty area, each time movi

Leviafan [203]

Answer:

W = 12.96 J

Explanation:

The force acting in the direction of motion of the sand paper is the frictional force. So, we first calculate the frictional force:

F = μR

where,

F = Friction Force = ?

μ = 0.92

R = Normal Force = 2.6 N

Therefore,

F = (0.92)(2.6 N)

F = 2.4 N

Now, the displacement is given as:

d = (0.12 m)(45)

d = 5.4 m

So, the work done will be:

W = F d

W = (2.4 N)(5.4 m)

5 0

4 years ago

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sladkih [1.3K]

Answer:

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3 years ago

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3 years ago