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mel-nik [20]
3 years ago
14

The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average,

it consumed 10 W of static power and 90 W of dynamic power.The Core i5 Ivy Bridge, released in 2012, had a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power.Find the percentage of the total dissipated power comprised by static power for the Pentium 4 Prescott. Round to a whole integer between 0-1
Physics
1 answer:
3241004551 [841]3 years ago
5 0

Answer:

For Pentium 4 Prescott:

% of Static Power = 10

For core i5 Ivy Bridge:

% of Static Power = 43

Given Information:

Static Power of P4 = 10 W

Dynamic Power of P4 = 90 W

Static Power of i5 = 30 W

Dynamic Power of i5 = 40 W

Required Information:

% of static power w.r.t total power dissipation = ?

Explanation:

For Pentium 4 Prescott:

% of static power = static power/total power * 100

% of static power = 10/(10 + 90) * 100

% of static power = 10/(100) * 100

% of static power = 10

For core i5 Ivy Bridge:

% of static power = static power/total power * 100

% of static power = 30/(30 + 40) * 100

% of static power = 30/(70) * 100

% of static power = 43 (rounded to nearest whole integer)

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For the material in the previous question that yields at 200 MPa, what is the maximum mass, in kg, that a cylindrical bar with d
Sedaia [141]

Answer:

The maximum mass the bar can support without yielding = 32408.26 kg

Explanation:

Yield stress of the material (\sigma) = 200 M Pa

Diameter of the bar = 4.5 cm = 45 mm

We know that yield stress of the bar is given by the formula

                Yield Stress = \frac{Maximum load}{Area of the bar}

⇒                                \sigma = \frac{P_{max} }{A}  ---------------- (1)

⇒ Area of the bar (A) = \frac{\pi}{4} ×D^{2}

⇒                            A  = \frac{\pi}{4} × 45^{2}

⇒                            A = 1589.625 mm^{2}

Put all the values in equation (1) we get

⇒ P_{max} = 200 × 1589.625

⇒ P_{max} = 317925 N

In this bar the P_{max} is equal to the weight of the bar.

⇒ P_{max} = M_{max} × g

Where M_{max} is the maximum mass the bar can support.

⇒ M_{max} = \frac{P_{max} }{g}

Put all the values in the above formula we get

⇒ M_{max} = \frac{317925}{9.81}

⇒ M_{max} = 32408.26 Kg

There fore the maximum mass the bar can support without yielding = 32408.26 kg

3 0
4 years ago
4. Three methods that people use are:
Mila [183]
The answers to question 4 d
6 0
3 years ago
A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s
Kobotan [32]
Well, st first we should find <span>initial momentum for the first person represented in the task which definitely must be :
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6 0
4 years ago
HELP.
Radda [10]

-- <em>Mechanical waves DO</em> require a medium in order to travel from place to place.  (Sound can't travel without some material to travel through on the way.)

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6 0
3 years ago
It takes 200 J of work to compress quasi-statically 0.40 mol of an ideal gas to one-fourth its original volume. Calculate the te
mario62 [17]

Answer : The temperature of the gas is, 43.4 K

Explanation :

The expression used for work done will be,

w=-nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 200 J

n = number of moles of gas  = 0.40 mol

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas  = X

V_2 = final volume of gas  = \frac{X}{4}

Now put all the given values in the above formula, we get :

200J=-0.40mol\times 8.314J/moleK\times T\times \ln (\frac{(\frac{X}{4})}{X})

T=43.4K

Thus, the temperature of the gas is, 43.4 K

3 0
4 years ago
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