Since you did not give a calculation,
I will just give an example. Suppose that you are to burn 5 kg of methane (CH4)
from 0 to 10°C. The specific heat capacity of methane is 4.475 kJ/kg-K.
H
= mCpT
H
= (5kg)( 4.475 kJ/kg-K)(10-0)
H = 223.75 kJ
Because the enthalpy is positive
in value, methane takes in heat.
His kinetic energy is converted into potential energy.
Answer:
$182 is the value of the gold in the coin
Explanation:
Diameter is 2r, the ratio of the coin is = 1.62cm / 2 = 0.81cm
Following the formula of the volume of the coin:
V = π r² h
V = π*(0.81cm)²*0.085cm
V = 0.172cm³ = mL
As the density of the gold is 19.32g/mL, the mass of 0.1752mL of gold is:
0.1752mL * (19.32g / mL) =
3.385g is the mass of the coin
As the price of the gold is $53.90 / g, the value of the gold in the coin is:
3.385g * ($53.90 / g) =
<h3>$182 is the value of the gold in the coin</h3>
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
