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4 years ago

Addition of a catalyst can speed up a reaction by providing an alternate reaction pathway that has a

Chemistry

1 answer:

kkurt [141]4 years ago

5 0

Answer:

Addition of a catalyst can speed up a reaction by providing an alternate reaction pathway that has a lower activation energy

Explanation:

A catalyst is an agent that increases the rate of a chemical reaction by providing an alternate pathway for the reaction that requires a lower activation energy. As the requirement for activation energy is less in the presence of a catalyst, there are more reactant particles becoming involved in the chemical reaction and as such there are more products formed per unit time, or there is an increase in the rate of the reaction

Example of catalyst include

1. Addition of potassium permanganate to hydrogen peroxide to aid in the rapid decomposition into water and oxygen

2. Platinum serves as a catalyst in the complete combustion of carbon monoxide into carbon dioxide.

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4 years ago

Why does solid water (ice) float when placed in liquid water? *

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3 years ago

The radius of a strontium atom is 215 pm. How many strontium atoms would have to be laid side by side to span a distance of 4.19

Solnce55 [7]

Answer:

0.97 × 10⁹ strontium atoms

Explanation:

if 1 pm is equal with 10⁻⁹ mm

then 215 pm are equal to X mm

X = (215 × 10⁻⁹) / 1 = 215 × 10⁻⁹ mm

Now the diameter of the strontium atom is twice the radius:

diameter = 215 × 10⁻⁹ × 2 = 430 × 10⁻⁹ mm

if 1 strontium atom have a diameter of 430 × 10⁻⁹ mm

then X strontium atom are needed to be laid said by side to span a distance of 419 mm

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8 0

3 years ago

A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is t

inn [45]

Answer:

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M