Solution
Problem 6
For this case we can do this:
12, 16,__, 14, 8, 7
We can solve for x like this:


Problem 7
F
So if you have 192 marbles and you want to group them in groups of 15 marbles each
you would see how many times 15's there are in 192 or how many 192's would go into 15
so 192/15 or
12 and 12/15
Answer:
Savannah
Step-by-step explanation:
1. Find the unit rate of all of the tables by dividing the values so that you know how much they earn per hour (ex. for Greg, the ratio is 3hours:$27 so divide all values by 3 to get 1hour:$9).
2. Compare all of the unit rate values (Savannah: $9.50 per hour, Greg: $9 per hour, and Kevin: $8.25 per hour).
You would do 20-6 which = 14. + 1 =15. times 8= 120 then divide that by 1/2 = 240 if you do 120 divided by .5 in a calculator thats what you get. i hope that helps you
A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5