Answer:
Let x be the number of silver medals.
As there were two more gold medals than silver ones, gold medals are x+2
We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.
Now, we can do an equation, as we know there were a total of 28 medals:
x + x + 2 + x + x + 2 - 4 = 28
And we isolate x:
4x = 28
x = 28/4 = 7
There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).
1/3 and 3/8
First, you would need to find the lowest common multiple.
It would be 24.
Change both fractions to fractions with a denominator of 24
1/3*8=8/24
3/8*3=9/24
You can see that 9 is greater that 8. Therefore 3/8 is greater.
Answer:
The answer is perpendicular to the base.
Step-by-step explanation:
Answer:
512 cm^3
Step-by-step explanation:
Divide 384 by 6 to find the surface area of one face of the cube. 384/6 = 64.
Find the square root of 64 to find both the length and width of the square. They are equal in a square.
= 8 = x
Volume = xyz or x^3
8^3 = 512