The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Answer:
A. (0, 60)
B. 15x
Step-by-step explanation:
The initial value is the same as the y-intercept, which is 60 or (0, 60).
The rate of change would be the same as the slope. To find the slope, you do rise/run. You move 15 units up, and 1 to the right. That would be 15x.
Hope this helps!
Answer:
62
Step-by-step explanation: