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Nata [24]
1 year ago
12

How many liters of water should be added to 20 liters of 40% solution of acid to

Mathematics
1 answer:
Ugo [173]1 year ago
8 0

The amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is:  6.7 Liters.

<h3>Liters of water needed</h3>

Acid = 0.4× 20

Acid = 8 liters

Water = 0.6× 20

Water = 12 liters

Acid/(Acid+Water)

A / (A + W) = 0.30

8 / (8 + W) = 0.30

2.4 + 0.3W = 8

0.3W = 8 - 2.4

0.3W= 5.6

Divide both side by 0.3W

W=5.6/0.3

W=18.7 Liters

18.7 - 12 = 6.7 Liters (Amount of water that must be added)

Therefore the amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is:  6.7 Liters.

Learn more about Liters of water needed here: brainly.com/question/23918882

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0.01

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c 5%

Step-by-step explanation:

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Factor and quadratic formula of 2x^2-11x=-5
katen-ka-za [31]

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x = 5

x = 0.5

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3 years ago
A music festival charges $54.95 per ticket sold on the day of the event. A ticket purchases before the festival costs only $39.9
Wewaii [24]
B=number of ticets sold before
a=number of tickets sold after

cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a

total cost=925000
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total number tickets=20000
b+a=20000

we have

39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000

15a=126000
divide bot sides by 15
a=8400

sub back
b+a=20000
b+8400=20000
minus 8400 both sides
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3 years ago
How are &lt;8 and &lt;4 related
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8 divided by 2 is 4

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