The amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is: 6.7 Liters.
Acid = 0.4× 20
Acid = 8 liters
Water = 0.6× 20
Water = 12 liters
Acid/(Acid+Water)
A / (A + W) = 0.30
8 / (8 + W) = 0.30
2.4 + 0.3W = 8
0.3W = 8 - 2.4
0.3W= 5.6
Divide both side by 0.3W
W=5.6/0.3
W=18.7 Liters
18.7 - 12 = 6.7 Liters (Amount of water that must be added)
Therefore the amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is: 6.7 Liters.
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Answer:
4.65
Step-by-step explanation:
3 and 1.
3 + 1 = 4
3^2 + 1^2 = 10
9 + 1 = 10
