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1 year ago

How many liters of water should be added to 20 liters of 40% solution of acid to

1 answer:

8 0

The amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is: 6.7 Liters.

<h3>Liters of water needed</h3>

Acid = 0.4× 20

Acid = 8 liters

Water = 0.6× 20

Water = 12 liters

Acid/(Acid+Water)

A / (A + W) = 0.30

8 / (8 + W) = 0.30

2.4 + 0.3W = 8

0.3W = 8 - 2.4

0.3W= 5.6

Divide both side by 0.3W

W=5.6/0.3

W=18.7 Liters

18.7 - 12 = 6.7 Liters (Amount of water that must be added)

Therefore the amount of liters of water that should be added to 20 liters of 40% solution of acid to obtain 30% solution is: 6.7 Liters.

Learn more about Liters of water needed here: brainly.com/question/23918882

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I need help with this, please.

n200080 [17]

Answer:

A: I think it's A because you need to graph both equations

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2 years ago

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What is the measurement of x in the equation. 8x+5x+2x-11+6=180

34kurt

Answer:

x = 37/3 = 12.333

Step-by-step explanation:

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

15x - 185 = 5 • (3x - 37)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 5 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : 3x-37 = 0

Add 37 to both sides of the equation :

3x = 37

Divide both sides of the equation by 3:

x = 37/3 = 12.333

4 0

2 years ago

Guys, please help me out. Thank you.

hichkok12 [17]

Answer:

50 Feet

Step-by-step explanation:

2L +2W = 148

L=1.5W+14

2(1.5W+14)+2W=148

3W+28+2W=148

5W=120

w=24

6 0

3 years ago

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This table shows the number of points a high school basketball team scored during each of its last 10 games.

professor190 [17]

The measure of central tendency that is most affected by the lowest score is; A: The mean.

<h3>How to find the measures of Central Tendency?</h3>

The points table is missing and so I have attached it.

The 3 main measures of central tendency are called mean, median and mode.

Now, from the table attached, if we find the average which is the mean, we will get 56.6.

Now, the mode is the number that occurs the most times. In this case, there is no mode because no number appears more than the other.

For the median, if we arrange in ascending order, we have;

42, 48, 49, 53, 55, 56, 58, 66, 68, 71.

The median = (55 + 56)/2 = 55.5

Now, if we remove the lowest score, the measure that will be most affected will be the mean as the median will only change by 0.5 to 56.

Read more about Measures of Central tendency at; brainly.com/question/17631693

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3 0

1 year ago

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0

2 years ago