given f(x)=4x-1, find the domain value if the range value is -5 given f(x)=4x-1, find the domain value if the range value is -5

After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pict

dezoksy [38]

Subtract the number she completed from what she had left to paint originally.

The fractions have different denominators so first step is to rewrite the fractions with a common denominator.

23/25 can be rewritten as 92/100

Now you have 78 21/100 - 34 92/100

Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.

78 21/100 becomes 77 121/100

Now subtract :

77 121/100 - 34 92/100

77-34 = 43

And 121/100 - 92/100 = 29/100

Combine to get 43 and 29/100

3 0

2 years ago

If it takes 100 g of sugar to make five cupcakes how many grams of sugar let me take to make 15 cupcakes

marissa [1.9K]

Answer:

300 g of sugar

Step-by-step explanation:

15 divided by 5 is 3 so 3 x 100 is 300. Hope this helps! :)

5 0

3 years ago

Read 2 more answers

(picture included) brainliest

Temka [501]

The answer is 2.5 (B)

4 0

2 years ago

HELPPPPP MEEEEEE Which one is not a solution to y = 3x - 5? A. (0, –5) B. (– 1, – 2) C. (5/3, 0) D. (2, 1)

nignag [31]

Answer:

Step-by-step explanation:

Let's examine the individual things

A. x=0 --> y=3.0-5=-5 True

B. x=-1 --> y=3.(-1)-5=-8 False

C. x=5/3 -->y=3(5/3)-5=0 True

D. x=2 --> y=3.2-5=1 True

Answer is B.

You don't understand, you can ask me :)

7 0

2 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

2 years ago