Question

Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an inequality that gives the number of kites Alan needs to sell to make at least $900 per week?

Answer 1

To pay website Alen needs to make 1 kite a day that is 7 kites.
To earn at least 900$ per week he needs to make 900$/20$=45kites
900/20+7=52 kites. Alen need to make at least 52 kites a week to earn at least 900$.

Answer 2

Answer:

52 kites

Step-by-step explanation:

We are given that

Profit of one kite=$20

He pays per day for his website=$20

Number of days in 1 week=7

Allen needs to sell to make atleast in 1 week=$900

We have to write an inequality that gives the number of kites.

Let x be the number of kites.

According to question

$20\times x-20\times 7 \geq 900$

$20x-140 \geq 900$

adding  140 on both sides

$20x+140-140\geq 900+140$

$20x\geq 1040$

Divide by 20 on both sides

$\frac{20x}{20}\geq \frac{1040}{20}$

$x\geq 52$

$x\geq 52$

Hence, Allens   need  to sell atleast 52 kites.