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BabaBlast [244]
2 years ago
12

Please help me with Algebra 2 problems.

Mathematics
1 answer:
grandymaker [24]2 years ago
8 0

Answer:

5)\ \ \left( x^{8}y^{4}\right)^{\frac{1}{10} }  +3\left( x^{\frac{1}{5}}y^{\frac{1}{10} \right)^4=4x^{\frac{4}{5}}y^{\frac{2}{5}}

6)\ \ \frac{2\sqrt{9^{5}} +7\sqrt{9^{5}} }{\sqrt{9^{7}} }=1

Step-by-step explanation:

\left( x^{8}y^{4}\right)^{\frac{1}{10} }  +3\left( x^{\frac{1}{5}}y^{\frac{1}{10} \right)^4

=x^{\frac{8}{10}}y^{\frac{4}{10}}  +3x^{\frac{4}{5}}y^{\frac{4}{10} }

=x^{\frac{4}{5}}y^{\frac{2}{5}}  +3x^{\frac{4}{5}}y^{\frac{2}{5} }

=x^{\frac{4}{5}}y^{\frac{2}{5}}\times(1+3)

=4x^{\frac{4}{5}}y^{\frac{2}{5}}

……………………………………

\frac{2\sqrt{9^{5}} +7\sqrt{9^{5}} }{\sqrt{9^{7}} }

=\frac{(2+7) \times\sqrt{9^{5}} }{\sqrt{9^{2}} \times \sqrt{9^{5}} }

=\frac{9 \times\sqrt{9^{5}} }{9 \times \sqrt{9^{5}} }

=1

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. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the
inn [45]

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

\frac{210}{x + 2}  =  \frac{150}{x}

X represents the speed of the second car. By cross multiplying, you get the following equation:

210x = 150(x + 20)

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.

4 0
2 years ago
What is 25% of 40? Show Work please
goldenfox [79]

25% = 1/4

1/4(40)

Divide 40 by 4 to remove the 1/4

10

25% of 40 is 10.

7 0
3 years ago
Read 2 more answers
If you decided to build a ramp using the 1:16 slope - ratio requirement , what would be the length of the diagonal portion of th
oee [108]
I spent a lil time on it but I’ll let you know in a lil but if I have the answer:)
4 0
2 years ago
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Can someone help me with this right answer only and please explain it too
sineoko [7]

Answer:

g(6) = 71

f(11) = 62

Step-by-step explanation:

Let's solve g(6) first

Plug 6 into x

g(6) = 2(6)^2 - 1

g(6) = 2(36) - 1

g(6) = 72 - 1

g(6) = 71

Now let's solve f(11)

f(11) = 5(11) + 7

f(11) = 55 + 7

f(11) = 62

<em>Thus, out answers are 71 and 62 respectively</em>

5 0
3 years ago
For which value of a does Limit of g(x) as x approaches alpha not exist?​
Hunter-Best [27]

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

#SPJ1

7 0
1 year ago
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