In slope-intercept form, the y variable is isolated.
so,
<span>13+5y=6x
Subtract 13 on both sides.
5y=6x-13
Divide by 5 on both sides.
y=6/5 x -13/5</span>
Answer:
d=2.5
Step-by-step explanation:
first find the coordinate of B(mid point of AC):A(3,7) C(6,11)
d=√(6-3)²+(11-7)²
d=√3²+4²
d=√9+16=√25=5
since B is the mid point : d/2=5/2=2.5
<h2>Another way :</h2>
B(x1+x2/2 , y1+y2/2) , x1=3 , x2=6, y1=7, y2=11
B(9/2,18/2)
B(9/2,9)
Find AB : the length or distance between 2 points:
d=√(x2-x1)²+(y2-y1)²
d=√(3-9/2)²+(7-9)²
d=√(-3/2)²+(-2)²
d=√1.5²+4
d=√6.25
d=2.5
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
C.64 and octagon has 8 sides and one side is 8cm so you multiply 8x8
