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irakobra [83]
3 years ago
6

Pls help me with this question

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

width of snow flake image = 1.8 cm

width of actual snow flake = 1/8 of image width = 1/8 × 1.8 = 18/80 = 9/40 = 0.225 cm

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Please anser. please answer. please answer. thank you.
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A) after 5 years she will pay $7,200
b) she will save $2880

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3 years ago
Find the value of x if the measures of the interior angles of a pentagon are 5x®, 10X, 10X°, 10x°, and 10X°.
fomenos

Answer:

is 1 i think

Step-by-step explanation:

8 0
3 years ago
Value of x in 23/-x=2/8
Stels [109]

Answer:

x=-92 is the answer I hope it helps

4 0
3 years ago
Read 2 more answers
Given: f(x) = 2x-1 and g(x) = 2x-3<br> Find:<br> (fog)(x)<br> HELP PLEASEE!!
Murljashka [212]

Answer:

(fog)(x) = 4x - 7

Step-by-step explanation:

f(x) = 2x-1 and g(x) = 2x-3;

(fog)(x) = f(g(x)

= f(2x - 3) = 2(2x - 3) - 1

= 4x - 6 - 1

= 4x - 7

7 0
3 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
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