A graph shows the first comparison is true, and the C temperature is cooler than the F temperature for the remaining comparisons.
The comparison that is FALSE is ...
C.....30 °C is warmer than 90 °F
_____
30 °C = 86 °F
32.2 °C ≈ 90 °F
Answer:
Here is your answer if thats is what you where asking for
Step-by-step explanation:
I really hope this helps! Look at the image I Uploaded.
Answer:
-ad-r=C
-------- Sorry thats the best I could do for a fraction symbol
3-b
Step-by-step explanation:
In order to solve for C we need to get it C on one side of the equation all by itself. To start we can subtract R from both sides and subtract bc from both sides to get both C's on one side. That gets us to
-ad-r=3c-bc
Since the side with C has a common factor, C between 3c and bc we can pull that out, and we get
-ad-r=c(3-b)
and then we just divide 3-b on both sides to get C completely by itself
-ad-r=C
--------
3-b
I hope this helps and please don't hesitate to ask if there is anything still unclear!
Salma showed me how to do it.
Here are two ways:
8 times (5·3 - 2) = 8 times (15 - 2) = 8 times 13 = 104 .
8 times (5·2 + 3) = 8 times (10 + 3) = 8 times 13 = 104.
Thank you, Salma.
Answer:
The interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.
Step-by-step explanation:
In statistics, the 68–95–99.7 rule, also recognized as the Empirical rule, is a shortcut used to recall that 68%, 95% and 99.7% of the values lie within one, two and three standard deviations of the mean, respectively.
Then,
- P (µ - σ < X < µ + σ) = 0.68
- P (µ - 2σ < X < µ + 2σ) = 0.95
- P (µ - 3σ < X < µ + 3σ) = 0.997
he random variable <em>X</em> can be defined as the amount of time a certain brand of light bulb lasts.
The random variable <em>X</em> is normally distributed with parameters <em>µ</em> = 1300 hours and <em>σ</em> = 90 hours.
Compute the interval of hours that represents the lifespan of the middle 68% of light bulbs as follows:
Thus, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.
