3 years ago

Find the lcm of each set of polynomials x^3-6x^2-16x,x^2-4

1 answer:

5 0

There is no LCM in this polynomial, unless it is -4x, which, in that case, the LCM would be x

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FromTheMoon [43]

Answer: $\frac{5}{7} (2+\frac{6}{r} )$

Step-by-step explanation:

Since, the quotient of 6 and r = $\frac{6}{r}$

The sum of two and the quotient of 6 and r

= $(2+\frac{6}{r} )$

And, Five-sevenths of the sum of two and the quotient of 6 and r

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Thus, the required expression is, $\frac{5}{7} (2+\frac{6}{r} )$

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3 years ago