67.50? i think... maybe double check though.
Answer:
y=1
Step-by-step explanation:
Answer:
The probability that the maximum speed is at most 49 km/h is 0.8340.
Step-by-step explanation:
Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.
The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.
To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.
The formula to convert <em>X</em> into <em>z</em>-score is:

Compute the probability that the maximum speed is at most 49 km/h as follows:
Apply continuity correction:
P (X ≤ 49) = P (X < 49 - 0.50)
= P (X < 48.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.
y axis is vertical x is horizontal
Step-by-step explanation:
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
2
+
6
+
4
=
0
2x^{2}+6x+4=0
2x2+6x+4=0
=
2
a={\color{#c92786}{2}}
a=2
=
6
b={\color{#e8710a}{6}}
b=6
=
4
c={\color{#129eaf}{4}}
c=4
=
−
6
±
6
2
−
4
⋅
2
⋅
4
√
2
⋅
2
x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}
x=2⋅2−6±62−4⋅2⋅4
brainliest and follow and thanks