Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,

Thus, the required equation of the line is y=x-8.
The correct answer for this is 6m - 5
That is the final expression.
Mark brainliest :)
Answer:
<em>39 is 26.71% of 146</em>
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 146 is 100% since it is our output value.
Step 2: We next represent the value we seek with x.
Step 3: From step 1, it follows that 100% = 146.
Step 4: In the same vein, x% = 39.
Step 5: This gives us a pair of simple equations:
100% = 146(1).
x%=39(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have
100/x% = 146/39
Step 7: Taking the inverse (or reciprocal) of both sides yields
x% / 100% = 39/146 ⇒ x= 26.71%
Therefore, 39 is 26.71% of 146.
<em>hope it helps:)</em>
Answer is 5^12 which is choice A (assuming you meant to put the ^ symbol)
The bases are the same (both are 5), so you add the exponents: 4+8 = 12. The base stays the same the entire time.
So, 5^4*5^8 = 5^(4+8) = 5^12