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alexandr1967 [171]
2 years ago
6

Which quadratic equation is equivalent to (x-4)² – (x − 4) − 6 = 0?

Mathematics
1 answer:
iren2701 [21]2 years ago
4 0

The quadratic equation u² - u - 6 = 0 where u = (x -4) is equivalent to (x-4)² – (x − 4) − 6 = 0 option (D) is correct.

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have a quadratic equation:

(x-4)² – (x − 4) − 6 = 0

Let (x - 4) = u

u² - u - 6 = 0

Thus, the quadratic equation u² - u - 6 = 0 where u = (x -4) is equivalent to (x-4)² – (x − 4) − 6 = 0 option (D) is correct.

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ1

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<img src="https://tex.z-dn.net/?f=%5Cblue%7B%5Cboxed%7B%5Cboxed%7B%5Csf%5Cblue%7BHELP%20ME%20PLEASE%7D%7D%7D%7D" id="TexFormula1
ruslelena [56]

Answer:

The completed two column proof is presented as follows;

Statement  {}                               Reason

1. AC bisects ∠A and ∠C {}       1. Given

2. ∠ACB ≅ ∠ACD {}                  2. Definition of bisector

3. ∠BAC ≅ ∠DAC     {}              3. Definition of bisector

4. \overline {AC} = \overline {AC}     {}                        4. Reflexive PE

5.  \overline {AC} ≅ \overline {AC}     {}                      5. Segments with equal lengths are congruent

6. ΔABC ≅ ΔADC   {}                6. By ASA

Step-by-step explanation:

The completed two column proof is presented as follows;

Statement  {}                              

1. AC bisects ∠A and ∠C; The given data on the figure

2. ∠ACB ≅ ∠ACD;{} A bisected angle is divided into two equal angles which are congruent to each other

3. ∠BAC ≅ ∠DAC     {}              3. Definition of bisector

4. \overline {AC} = \overline {AC}     {}                        4. Reflexive Property of Equality (PE)

5.  \overline {AC} ≅ \overline {AC}     {}                      5. Segments with equal lengths are congruent

6. ΔABC ≅ ΔADC   {}                6. By Angle-Side-Angle, ASA, is a condition for congruency of two triangles

Where two angles and the included side between the two angles on one triangle are equal to two angles and the included side between the two angles on another triangle, the two triangles are said to be congruent by the Angle-Side-Angle ASA rule and therefore, they each have equal measures for all corresponding angles sides.

6 0
3 years ago
Can someone please help me with this assignment
KIM [24]
These are 8 questions and 8 answers.

Page 1:

1) Triangle ABC has vertices A(-2,1), B(0,5), and C (8,1). What type of triangle is triangle ABC


Answer: option A. acute triangle.

Explanation:

Determine the lengths of the three sides:

Side AB: √[(0+2)^2 + (5-1)^2 ] = √ [4 + 16] = √(20)

Side BC: √ [ (8-0)^2 + (1 -5)^2 ] = √ [ 64 + 16 ] = √(86)

Side AC: √ [ (8 + 2)^2 + (1 - 1)^2 ] = √100 = 10

Compare the square of the side length of the largest side with the sum of the squares of the other two sides.:

AC^2 = 100
BC^2 = 86
AB^2 = 20

BC^2 + AB^2 = 86 + 20 = 106

100 < 106 => AC^2 < BC^2 + AB^2 =>

all the angles are less than 90°, which means the triangle is actue.

That is becasue when the square of the largest side is equal to the sum of the squares of the smaller sides, there is a right angle and the triangle is a right triangle (Pytaghorean theorem). When the square of the largest side is less than the sum of the squares of the other two sides, the angle is less than 90°, and the triangle is acute.

2) Which set represents the side lengths of a right trianle?

Answer: option C: 9, 12, 15

Explanation:

Check whic set obeys Pythagorean theorem.

15^2 = 225
12^2 = 144
9^2 = 81
.
144 + 81 = 225 => 15^2 = 12^2 + 9^2 => right triangle

3) Which property disproves the statement in the student's notes?

Answer: option B) all angles of a rhombus are not congruent.

Explanation:

A rhombus is a quadrilateral whose four sides all have the same length. It is a quadrilateral.

The angles do not need to be congruent. Only the square, which is only one special case of rhombus, has the four angles congruent, but the masure of the angles of other rhombus are not equal.

4) What is the are of the figure?

Answer: 85 unit^2

Explanation:

1) Area of the rectangle = base * height  = 4 * 9 = 36
2) area of the trapezoid = height * half of the sum of the bases = 7 * (3+7)/2 = 35
3) area of the rhombus = half the product of the diagonals = 7 * 4 / 2 = 14

Result: 36 + 35 + 14 = 85

That option is not among the choices. The nearest one is 84 unit^2.

Page 2 is the same page 1.

Page 3:

5) Question 8:

What line can be used to draw the altitude of the triangle FGH

Answer: option D: 3y = 7x + 16

Explanation:

1) All triangles have 3 altitudes (one for each vertex).

2) Now I am going to find the altitude of the vertex H (respect to base FG.

3) First calculate the slope of the segment FG:

slope = [y2 - y1] / [x2 - x1]

x2, y2 are the coordinates of the point G (6, -2) and x1, y1 are the coordinates of the point F (-8,4)

=> slope = [ -2 - 4] / [6 - (-8) ] = [-6] / [14] = - 3/7

4) Now calculate the slope of the perpendicular line (because the altitude is perpendicular to the base).

The lines of perpendicular lines obey the rule: slope line A = - slope line B / 2

So, the slope of the line perpendicular to the base is - [1 / (-3/7) ] = 7/3

5) The equation of the line with slope 3/7 that contains the point H (-4, - 4) is:

y - (-4)        7
--------- =  -----
x - (-4)       3

=> 3(y + 4) = 7(x + 4)

=> 3y + 12 = 7x + 28

=> 3y = 7x + 28 - 12

=> 3y = 7x + 16 which is the answer

6) Question 8. How will be the volume affected

Answer: option c. the volume will be 9 times larger.

Explanation:

1) Formula of the volume of rectagular prism

Volume = length * width * height

2) Name, V the volume, l the length, w the width, h the heigth => V = l * w * h

3) Triple the length and the width:

New volume = 3l * 3w * h = 9 l * w * h = 9V

4) You have proved that the new volumen is 9 times the original volume, which is the option c.


7) Question 9

What is the approximate length of the median of the trapezoid ABCD.

Answer: option b. 7.8 units

Explanation:

1) The median of a trapezoid is half the sum of the two parallel segments

2) The two parallel segments are AB and CD

3) The length of the segment AB is:

AB^2 = (3+7)^2 + (7-2)^2 = 10^2 + 5^2 = 100 + 25 = 125

=> AB = √125 ≈ 11.18

4) The length of the sement CD is:

CD^2 = (3 + 1)^2 + (1+1)^2 = 4^2 + 2^2 = 16 + 4 = 20

=> CD = √20 ≈ 4.47

5) The median is [11.48 + 4.47] / 2 ≈ 7.83 => option b.

8) Question 10. Problem

Answer: option B. 34.8 feet

Explanation:

1) Variables:

Ha = 4 ft (heigth of Abigail)
α = 38°
s = 50 ft (length of the string)
Hk = ? (altitude of the kite)

2) formula of sine ratio:

sin α = opposite-leg / adjacent leg

3) solution

sin α = x / s => x = sinα * s = sin(38°) * 50 ft = 30.78 ft

Hk = x + Ha = 30.78 ft + 4 ft = 34.78 ft => aption B. 34.8 feet
8 0
3 years ago
What is 4/15 as a decimal and percent?
mamaluj [8]
4/15 is a repeating decimal. 
Decimal- 0.2666...
Percent- 26.66...%
Rounded Decimal- 0.267
Rounded Percent- 26.67%
3 0
4 years ago
How do you solve simple linear equations?
Firlakuza [10]

9514 1404 393

Explanation:

The rules of equality tell you that you can do anything you like to an equation, as long as you do the same thing to both sides of the equal sign. This is the essence of Algebra, so is worth remembering. My teacher summarized it as "keep the equal sign sacred."

__

"Simple linear equations" come in several varieties. They are sometimes called "one-step", or "two-step", or "three step" linear equations, depending on how many steps are required to solve them. In what follows, we're using "x" as the variable, and the letters a, b, c, d as constants.

<u>One-step</u>

In general, the "one step" will be either an addition or a multiplication.

  x + a = b . . . . an addition equation

  ax = b . . . . . . a multiplication equation

The key in any case is to look at what is done to the variable and use an inverse operation to "undo" it. The opposite of addition is addition of the additive inverse (add the opposite). This is also called subtraction. For the addition equation, this looks like ...

  x + a - a = b - a . . . . . . add (-a) <em>to both sides </em>(or subtract 'a')

  x = b - a . . . . . . . . . . . the solution

The opposite of multiplication is multiplication by the multiplicative inverse (the reciprocal) This is also called division. For the multiplication equation, this looks like ...

  ax(1/a) = b(1/a) . . . . . multiply by (1/a) <em>on both sides</em> (or divide by 'a')

  x = b/a . . . . . . . . . . . the solution

__

<u>Two-step</u>

As with one-step linear equations, two-step equations come in some different forms.

  ax +b = c

  ax +b = cx

  a(x +b) = c

In general, the two steps are an addition step and a multiplication step, not necessarily in that order. You will notice that the first step can transform the equation to a "one-step" equation. As before, inverse operations are involved, and whatever is done is done to both sides of the equal sign.

  ax +b = c   ⇒   ax = (c -b) . . . . subtract b to get a multiplication equation

In this next, we have the variable on both sides of the equal sign. we can put the variable on one side of the equal sign by adding the opposite of the term we don't want where it is. Leaving the constant alone, we can add (-ax) to both sides to get ...

  ax +b = cx   ⇒   b = cx -ax   ⇒   b = (c -a)x

When you have numbers, you can go directly to (c-a)x by "combining terms". This is now the one-step multiplication equation.

Finally, another 2-step form is ...

  a(x +b) = c   ⇒   x +b = c/a . . . . . divide by 'a' to get an addition equation

This last equation can also be solved by using the distributive property first.

  ax +ab = c . . . . . still a 2-step equation, now of the first type

__

<u>Three-step</u>

The most typical "3-step" linear equation is of the form ...

  ax +b = cx +d

where both variables and constants are on both sides of the equal sign. As you may have noticed above, we prefer to have variables on one side and constants on the other side. So, add the opposite of the term you don't want where it is (to both sides, of course).

If we want variables on the left and constants on the right, we can add -cx and -b. The "3 steps" assume you do these as separate operations.

  ax +b -cx = cx +d -cx   ⇒   (a-c)x +b = d . . . a two-step equation

  (a-c)x +b -b = d -b    ⇒   (a-c)x = d-b . . . . a one-step multiplication equation

_____

<em>Additional comments</em>

There are some choices you can make that will tend to reduce errors. One of them involves selection of the variable term you want to eliminate (add the opposite of). Generally, if you choose the term with the lowest (most negative, left-most on the number line) coefficient, adding its opposite will result in a positive coefficient for the remaining variable term. Then when you divide by that coefficient, you're dividing by a positive number. Most folks perform arithmetic with fewer errors when they're working with positive numbers.

The general approach to any "solve for" situation is to look at what is done to the variable you're solving for. The Order of Operations is a useful lens for looking at this. When you list the operations, your "undo" sequence will start with the last operation on the list, and work backward.

<em>Further note</em>: your total comfort with doing arithmetic with any kind of numbers (integers, fractions, mixed-numbers, decimals, scientific notation, positive or negative) will aid you immensely. Always be careful with minus signs. They tend to get lost, forgotten, ignored, Be sure they don't.

8 0
3 years ago
Plz help me well mark brainliest if correct!!......
Elenna [48]

Answer:

Option C

Step-by-step explanation:

have a great Day

8 0
3 years ago
Read 2 more answers
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