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mr_godi [17]
2 years ago
9

Show how to solve it step by step tan(x)cot(x)=1

Mathematics
1 answer:
nika2105 [10]2 years ago
3 0

There are two ways to confirm the identity.

Method 1

\tan(x)\cot(x) = 1\\\\\tan(x)\frac{1}{\tan(x)} = 1\\\\\frac{\tan(x)}{\tan(x)} = 1\\\\1 = 1 \ \ \checkmark\\\\

--------------------------------------------

Method 2

\tan(x)\cot(x) = 1\\\\\left(\frac{\sin(x)}{\cos(x)}\right)\left(\frac{\cos(x)}{\sin(x)}\right) = 1\\\\\frac{\sin(x)\cos(x)}{\cos(x)\sin(x)} = 1\\\\\frac{\sin(x)}{\sin(x)} = 1\\\\1 = 1 \ \ \checkmark\\\\

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2x + 5y = 6
Snezhnost [94]

Step-by-step explanation:

Given equations

2x + 5y = 6 .......i)

2x = 10 - 3y...... II)

Putting 2x = 10 - 3y in equation i

10 - 3y + 5y = 6

2y = 6 - 10

2y = - 4

y = - 4 / 2

y = - 2

Now putting y = - 2 in equation ii

2x = 10 - 3 * ( - 2)

2x = 10 + 6

2x = 16

x = 16 / 2

x = 8

So x = 8 and y = - 2

Hope it will help :)❤

7 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a labatory . colby starts with 50 bacteria and the number of bacteria
cricket20 [7]

Answer:400

Step-by-step explanation:

3 hours: 400 times 2=800

6 hours: 800 times 2=1600

9 hours: 1600 times 2=3200

12 hours: 3200 times 2=6400

15 hours: 6400 times 2= 12800

18 hours: 12800 times 2=25,600

21 hours: 25,600 times 2= 51200

24 hours: 102,400

7 0
3 years ago
If the 5th term of a geometric progression is 162 and the 8th term is 4374, find the (i) 1st three terms of the sequence; (ii) s
Alona [7]

Answer:

see explanation

Step-by-step explanation:

The nth term of a geometric progression is

a_{n} = a₁r^{n-1}

where a₁  is the first term and r the common ratio

Given a₅ = 162 and a₈ = 4374 , then

a₁r^{4} = 162 → (1)

a₁r^{7} = 4374 → (2)

Divide (2) by (1)

\frac{a_{1}r^{7}  }{a_{1}r^{4}  } = \frac{4374}{162}

r³ = 27

r = \sqrt[3]{27} = 3

Substitute r = 3 into (1) and solve for a₁

a₁(3)^{4} = 162

81a₁ = 162

a₁ = \frac{162}{81} = 2

Then

a₂ = a₁ × 3 = 2 × 3 = 6

a₃ = a₂ × 3 = 6 × 3 = 18

The first 3 terms are 2, 6, 18

(ii)

The sum to n terms of a geometric progression is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1} , then

S_{10} = \frac{2(3^{10}-1) }{3-1}

     = \frac{2(59049-1)}{2}

     = 59049 - 1

     = 59048

   

6 0
3 years ago
How much would Umesh get paid for travel allowance for 120kms a day @75cents?
Igoryamba
In this question the main trick lies in the fact that Umesh is getting paid at the rate of 75 cents per kilometer. It has to be converted to dollars for getting to the correct answer. Now let us get down to the problem in hand
75 cents = 0.75 dollars
Then
For 1 kilometer of travel Umesh gets paid = 0.75 dollars
So
For 120 kilometers of travel in a day, Umesh will get paid = 120 * 0.75 dollars
                                                                                            = 90 dollars
From the above deduction we can easily conclude that the travel allowance for Umesh for the day will be $90. I hope this has helped you.
6 0
3 years ago
Read 2 more answers
The diagram shows corresponding lengths in two similar figures. Find the ratio of the areas of the two figures.
astra-53 [7]
Your answer should be D. 49.81
5 0
3 years ago
Read 2 more answers
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