Set up the math. But don’t do any of it. Just leave your answer as a math expression. Also be should you’re answering includes a
ll the correct unit symbols.
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In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
We will see that the volume of the unit cell is 144,070,699.06 pm^3
<h3>How to get the volume of a body-centered cubic unit cell?</h3>
In a body-centered cubic unit cell, the side length of the cube is given as:
Where R is the radius of the atom.
And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:
Solving that we get:
This is the approximated volume of the unit cell.
If you want to learn more about unit cell structures, you can read:
Explanation:
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