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kicyunya [14]
3 years ago
13

Plz help me in this Question (i) and (ii) and (iii)

Chemistry
1 answer:
gregori [183]3 years ago
7 0

The answer is given below....

Hope it helps

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Which is a nonmetal that becomes isoelectronic with argon<br> when it forms its most common ion?
mrs_skeptik [129]

Answer:sulfur

Explanation:

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3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

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3 years ago
What is a cold front
Vlada [557]
A cold front is the leading edge of a cooler mass of air, replacing at ground level a warmer mass of air, which lies within a fairly sharp surface trough of low pressure.
4 0
3 years ago
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Identify an alkene and carboxylic acid using primary observations
ehidna [41]

Answer:

The general formula for the carboxylic acids is C nH 2n+1COOH (where n is the number of carbon atoms in the molecule, minus 1).

Explanation:

<em>Hope </em><em>it </em><em>helps </em><em>u </em>

FOLLOW MY ACCOUNT PLS PLS

4 0
3 years ago
What is the specific heat of the solid phase? (Please see picture attached)
ValentinkaMS [17]

Answer:

B.0.2 J/g°C

Explanation:

From the attached picture;

  • Heat attained in the solid phase is 200 Joules
  • Change in temperature is 50°C ( from 0°C to 50°C)
  • Mass of the solid is 20 g

We are required to determine the specific heat capacity of the substance;

  • We need to know that Quantity of heat is given by the product of mass,specific heat capacity and change in temperature.
  • That is; Q = mcΔT

Rearranging the formula;

c = Q ÷ mΔT

Therefore;

Specific heat = 200 J ÷ (20 g × 50°c)

                      = 0.2 J/g°C

Thus, the specific heat of the solid is 0.2 J/g°C

4 0
3 years ago
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