Answer:
Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Assemble all the data in one place, with molar masses above the formulas and other information below them.
Mᵣ: 58.44
NaCl + AgNO₃ ⟶ NaNO₃ + AgCl
m/g: 0.245
V/mL: 50.
c/mmol·mL⁻¹: 0.0180
2. Calculate the moles of each reactant
3. Identify the limiting reactant
Calculate the moles of AgCl we can obtain from each reactant.
From NaCl:
The molar ratio of NaCl to AgCl is 1:1.
From AgNO₃:
The molar ratio of AgNO₃ to AgCl is 1:1.
AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.
4. Calculate the moles of excess reactant
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
I/mmol: 0.900 4.192 0
C/mmol: -0.900 -0.900 +0.900
E/mmol: 0 3.292 0.900
So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.
5. Calculate the concentration of Cl⁻
Answer:
5.12 L
Explanation:
P1V1/T1 = P2V2/T2
1.71 atm *10.0L /100 K = 9.70 atm *x/290.29 K
x = 1.71 atm *10.0L*290.29K /(100 K * 9.70 atm)= 5.12 L
Activation energy?? The energy needed to start a chemical reaction is called activation energy
Answer:
True
Explanation:
All the chemical elements have their abbreviations as one or two letters
The first letter in the abbreviation is a capital letter and the second letter is always a small letter
Majority of abbreviations are based on their english names