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emmainna [20.7K]
1 year ago
5

To solve -3 = -19 + d/5, what steps would you use?

Mathematics
1 answer:
Pachacha [2.7K]1 year ago
8 0

To solve the expression, the steps are add 19 and multiply by 5

<h3>How to solve the expression</h3>

Given the equation;

-3 = -19 + d/5

First,

Collect like terms

-3+ 19 = d/5

Add the values on the left side

We have

16 = d/5

Cross multiply

16 × 5 = d

We then have

d = 80

Thus, to solve the expression, the steps are add 19 and multiply by 5

Learn  more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

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saveliy_v [14]
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. For the function y= -5x2 - 10x + c, the vertex is (-1,8). What is c? F. -13 G. -3 - J. 13 H. 3​
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Step-by-step explanation:

8=-5(-1)^2-10(-1)+c

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in 2002, a 30 second commercial during super bowl cost an average of 1,900,000. At this rate, how much would a 45 second commerc
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This is a unit multiplier of sorts

1,900,000 x 45/30

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3 years ago
Given sinx+1/sinx=1+cscx, find a numerical value of one trigonometric function of x.
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Answer:

x = π/2 or

x = π/2 + 2πn (for any value of n)

Step-by-step explanation:

We need to find the numerical value of the trigonometric function sinx+1/sinx=1+cscx

Subtract 1+cscx on both sides

sinx + 1/sinx -(1+csc x) = 1+cscx - (1+cscx)

sinx + 1/sinx -1 -csc x = 0

Taking LCM i.e, sinx and solving

(sinx)(sinx) + 1 - sinx -cscx(sinx) / sinx = 0

Multiplying sinx on both sides

sin^2 x + 1 -sinx - cscx(sinx) =0

as we know, cscx = 1/ sinx

sin^2 x + 1 -sinx - (1/sinx)(sinx) = 0

Solving,

sin^2 x + 1 -sinx - 1 = 0

sin^2 x - sin x =0

Let u = sinx

Putting it in above equation

u^2 - u =0

Solving the equation:

u= 1 , u= 0

Putting back the value of u

sin(x) = 1 and sin(x) = 0

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x = 90° or π/2 and x = 0 (undefined for the question)

So, x = π/2 or

x = π/2 + 2πn (for any value of n)

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