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2 years ago

Can someone explain what to do

Mathematics

1 answer:

castortr0y [4]2 years ago

7 0

Answer:

Step-by-step explanation:

The equation of the parabola can be represented as

$y = a(x + 1)(x - 5)$

for some constant a.

Since the coefficient of x² is 2, a = 2, so

$y = 2(x + 1)(x - 5) \\ \\ y = 2( {x}^{2} - 4x + 5) \\ \\ y = 2 {x}^{2} - 8x + 10$

So, the answer is 8.

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16= -5+z/4<br> a. 69<br> b. -1<br> c. 9<br> d. 59

vlada-n [284]

If you would like to solve the equation 16 = (- 5 + z) / 4, you can do this using the following steps:

16 = (- 5 + z) / 4 /*4
16 * 4 = - 5 + z
16 * 4 + 5 = z
z = 69

The correct result would be a. 69.

6 0

3 years ago

Read 2 more answers

What is the volume of the pyramid in the diagram?

Elan Coil [88]

Answer:

this question answer is 1500cm^3

5 0

3 years ago

What's the missing number?What is the rule?

MrMuchimi

Ok so for 1000m= 1km that means since 500 is half of 1000, 1/2 is half of 1

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3 years ago

Help! With Fraction Problems??? Hailey is knitting a scarf. Each half hour, she adds 3/7 inch to the scarf's length. How much le

seropon [69]

3x12= 36
7x12= 84
Answer:
36/84

6 0

3 years ago

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

ANSWER:

$x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}$

3 0

1 year ago