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SVEN [57.7K]
2 years ago
7

What's the value? (yelping for help)

Mathematics
2 answers:
horsena [70]2 years ago
6 0

cos(20°) is the correct answer.

Congratulations! This is the unit circle. Literally everyone hates this. Everyone takes this in Trigonometry though, and it's required. I literally failed Trigonometry because of this and had to retake it when getting my degree in Mathematics.

So, what is the x-coordinate of this? Well, for any angle or (angle in triangle) \alpha, the coordinates are always (cos(\alpha), sin(\alpha)).

In this case, angle \alpha is 20°, and so the x-coordinate will be cos(20°) while the y-coordinate will be sin(20°).

Hope this helped!

Natasha_Volkova [10]2 years ago
6 0

Answer: cos 20

Step-by-step explanation:

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If (x 2y)dy/dx=2x-y what is the value of.
Radda [10]

The second differential of the function is 3/7

Given the differential function (x +2y)=\frac{dy}{dx} (2x-y)

Differentiate both sides with respect to x implicitly

(x +2y)=\frac{dy}{dx} (2x-y)

1+2y'=y"(2x-y)+y'(2-y')  \\y''=\frac{1+2y'}{(2x-y)+y'(2-y') }

Get the first derivative at the point (3, 0)

y'=\frac{2x-y}{x+2y} \\y'=\frac{2(3)-0}{0+2(3)}\\y'=\frac{6}{6} \\y'=1

Substitute into the second derivative to have:

y''=\frac{1+2y'}{(2x-y)+y'(2-y') }\\y''=\frac{1+2(1)}{(2(3)-0)+(1)(2-(1)) }\\y''=\frac{3}{6+1} \\y''=\frac{3}{7}

Hence the second differential of the function is 3/7

learn more on differential equation here; brainly.com/question/18760518

Complete question:

If (x 2y)dy/dx=2x-y what is the value of \frac{d^2y}{dx^2} the point (3,0)

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