Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).
answer: (-oo;0.5b²)
Answer:
The answer to your question is w = 1.2
Step-by-step explanation:
Data
Equation 7(w + 2) + 0.5w = 5
Expand 7w + 14 + 0.5w = 5
Simplify like terms (7w + 0.5w) + 14 = 5
7.5w + 14 = 5
Subtract 14 in both sides
7.5w + 14 - 14 = 4 - 15
Simplify
7.5w = - 9
Divide both side by 7.5 7.5/7.5w = 9/7.5
Simplify
w = 1.2
The answer for 50 is (61-7 divides by 7)times 1/2+17
Realize "%" means "/100".
26 2/5% = 26.4% = 26.4/100 = 264/1000 = 0.264
