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3 years ago

Help me i need help badly again

Mathematics

1 answer:

Irina-Kira [14]3 years ago

8 0

Alright, given that it's a male then

total of 4+6+2+2 or 14 pepole are male
4 of them are freshmen

so the probalbity would be 4/14 or 2/7 or aprox 0.28571428571428571428571428571429

about 29%

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astraxan [27]

Answer:

I hope this helps you hehehe :)

7 0

3 years ago

Read 2 more answers

Penny wants to make a model of a beetle that is larger than life size. Penny says she is going to use a scaling factor of 7/12.

MakcuM [25]

It would be nonsense, as if the beetle were at normal size, then it would be considered 1/1 as a scale. If you wanted to increase it, you would increase the numerator.

4 0

2 years ago

Read 2 more answers

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money an

Alenkasestr [34]

Answer:

The money each boy had after buying his ticket is $2.50.

Step-by-step explanation:

Given:

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money and spent $7.50 on a ticket.

Now, to find the money each boy had after buying his ticket.

Let the money each boy had after buying his ticket be $x.$

Total number of boys = 4.

Total money they had = $40.

Money each boy spent = $7.50.

Now, to write an equation:

$4(x+7.50)=40$

Now, to solve the equation for getting the money each boy had after buying his ticket:

$4(x+7.50)=40$

$4x+30=40$

Subtracting both sides by 30 we get:

$4x=10$

Dividing both sides by 4 we get:

$x=\$2.50.$

Therefore, the money each boy had after buying his ticket is $2.50.

3 0

3 years ago

would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne

Leni [432]

The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.

The last example is solved in the same way.

8 0

3 years ago

Determine if the following system of equations has no solutions, infinitely many

mylen [45]

This are similar answers to your questions.

8 0

2 years ago