Can someone help me please its geometry.
1 answer:
The figure showing the construction is given below.
Steps for the construction of a circle through three points not on a straight line are as follows:
1. To create two lines, connect the points.
2. Create the line's perpendicular bisector.
3. Create the opposite line's perpendicular bisector.
4. The circle's center is where they intersect.
5. Draw your circle by placing the compass on the center point and adjusting its length to reach any point.
What happens if the points are parallel?
The circle traveling through all three points will have an infinite radius if the three points are collinear, or all situated on a straight line. Therefore, a practical circle cannot traverse three collinear locations. The two radii would be parallel and would never come together at a center if you tried the construction. We may claim that they do cross mathematically but at infinity.
Hence, after following the steps we obtain the circle.
Learn more about constructions here-
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Answer: Choice C) Multiplication property of inequality
The rule basically says that if you start with a < b and you multiply both sides by some positive number c, then a*c < b*c. The sign doesn't flip if you multiply both sides by a positive number.
The sign will flip if c is negative. So we'll go from a < b to a*c > b*c if c is negative.
Example 1:
1 < 5
-2 > -10 ... multiplied both sides by -2; sign flips
Example 2:
3 < 7
9 < 21 ... multiplied both sides by 3; sign does not flip
Similar rules apply to a > b,
and 
The rule basically says that if you start with a < b and you multiply both sides by some positive number c, then a*c < b*c. The sign doesn't flip if you multiply both sides by a positive number.
The sign will flip if c is negative. So we'll go from a < b to a*c > b*c if c is negative.
Example 1:
1 < 5
-2 > -10 ... multiplied both sides by -2; sign flips
Example 2:
3 < 7
9 < 21 ... multiplied both sides by 3; sign does not flip
Similar rules apply to a > b,